Per il 25/1

Post date: Jan 20, 2018 12:11:48 PM

Calcola i seguenti limiti di successione per n→∞ :

• • (n+ sen n)/(n + cos 3n)

  • (sen² n )/n²

  • 1/(√(n²-5) - √(n²-4))

  • (n+5)(1/√n - 1/√(n+1))

  • (5 n⁷ - 3 n³ + 7n)/(3 cos n - 5 n⁷)

  • 4ⁿ^-³ / (3ⁿ + 3)

  • 1/(1 - √[(n²+9)/(n²+1)] )

  • 1/(√(3n-1) - √(3n+9))

  • (5n⁴-n³)/(9n³-2n⁴)

  • (6n⁵-n³)/(4n³-n⁴)

  • (6n⁴-n³)/(5n³-3n⁴)-(2n⁵-n³)/(2n³-n⁵)

• (1 + 1/n)^-n

• (1 - 1/n)ⁿ