1. What is a parabola?
A parabola is a curved graph with a very special shape: it goes down and then up, or up and then down.
You can find parabolas in real life:
the path of a ball when you throw it,
the shape of some bridges,
the shape of satellite dishes,
the water coming out of a fountain,
the path of a basketball shot.
In mathematics, parabolas usually appear when we study quadratic functions.
A quadratic function is a function whose formula includes an x2x^2x2 term.
For example:
y=x2y=x^2y=x2 y=2x2y=2x^2y=2x2 y=x2+3y=x^2+3y=x2+3 y=−x2+4y=-x^2+4y=−x2+4
Let’s make a table of values for:
y=x2y=x^2y=x2
xxx
y=x2y=x^2y=x2
-3
9
-2
4
-1
1
0
0
1
1
2
4
3
9
If we represent these points on a graph, we get a parabola.
The graph of y=x2y=x^2y=x2:
opens upwards,
has its lowest point at (0,0)(0,0)(0,0),
is symmetric,
has a U-shape.
The point (0,0)(0,0)(0,0) is called the vertex.
The vertex is the turning point of the parabola.
It can be:
the lowest point, if the parabola opens upwards;
the highest point, if the parabola opens downwards.
Examples:
y=x2y=x^2y=x2
The vertex is:
(0,0)(0,0)(0,0) y=x2+2y=x^2+2y=x2+2
The vertex is:
(0,2)(0,2)(0,2) y=−x2+5y=-x^2+5y=−x2+5
The vertex is:
(0,5)(0,5)(0,5)
Look at these two functions:
y=x2y=x^2y=x2 y=−x2y=-x^2y=−x2
The first one opens upwards.
The second one opens downwards.
The sign of the x2x^2x2 term is very important:
Function
Shape
y=x2y=x^2y=x2
Opens upwards
y=−x2y=-x^2y=−x2
Opens downwards
So:
if the coefficient of x2x^2x2 is positive, the parabola opens upwards;
if the coefficient of x2x^2x2 is negative, the parabola opens downwards.
Examples:
y=3x2y=3x^2y=3x2
opens upwards.
y=−2x2y=-2x^2y=−2x2
opens downwards.
Compare these functions:
y=x2y=x^2y=x2 y=2x2y=2x^2y=2x2 y=4x2y=4x^2y=4x2
The larger the number multiplying x2x^2x2, the narrower the parabola becomes.
Now compare:
y=x2y=x^2y=x2 y=0.5x2y=0.5x^2y=0.5x2 y=0.25x2y=0.25x^2y=0.25x2
The smaller the number multiplying x2x^2x2, the wider the parabola becomes.
Function
Shape
y=4x2y=4x^2y=4x2
Narrower
y=x2y=x^2y=x2
Normal
y=0.25x2y=0.25x^2y=0.25x2
Wider
Look at these functions:
y=x2y=x^2y=x2 y=x2+3y=x^2+3y=x2+3 y=x2−2y=x^2-2y=x2−2
The number added at the end moves the parabola vertically.
Function
Movement
y=x2+3y=x^2+3y=x2+3
Moves 3 units up
y=x2−2y=x^2-2y=x2−2
Moves 2 units down
So:
y=x2+ky=x^2+ky=x2+k
moves the parabola:
up if k>0k>0k>0,
down if k<0k<0k<0.
Examples:
y=x2+5y=x^2+5y=x2+5
The vertex is (0,5)(0,5)(0,5).
y=x2−4y=x^2-4y=x2−4
The vertex is (0,−4)(0,-4)(0,−4).
A parabola is symmetric. This means that one half is a mirror image of the other half.
For the function:
y=x2y=x^2y=x2
the axis of symmetry is the vertical line:
x=0x=0x=0
This line passes through the vertex.
For these functions:
y=x2+3y=x^2+3y=x2+3 y=x2−5y=x^2-5y=x2−5
the axis of symmetry is still:
x=0x=0x=0
because the parabola has only moved up or down.
The y-intercept is the point where the graph crosses the y-axis.
To find it, we use:
x=0x=0x=0
Example:
y=x2+2y=x^2+2y=x2+2
If x=0x=0x=0:
y=02+2=2y=0^2+2=2y=02+2=2
So the y-intercept is:
(0,2)(0,2)(0,2)
The x-intercepts are the points where the graph crosses the x-axis.
To find them, we use:
y=0y=0y=0
Example:
y=x2−4y=x^2-4y=x2−4
We solve:
0=x2−40=x^2-40=x2−4 x2=4x^2=4x2=4 x=2orx=−2x=2 \quad \text{or} \quad x=-2x=2orx=−2
So the x-intercepts are:
(−2,0)(-2,0)(−2,0)
and
(2,0)(2,0)(2,0)
Some parabolas have:
two x-intercepts,
one x-intercept,
no x-intercepts.
Examples:
y=x2−4y=x^2-4y=x2−4
has two x-intercepts.
y=x2y=x^2y=x2
has one x-intercept.
y=x2+4y=x^2+4y=x2+4
has no x-intercepts.
A parabola can be increasing or decreasing depending on the part of the graph.
For:
y=x2y=x^2y=x2
the parabola:
is decreasing when x<0x<0x<0,
reaches its minimum at x=0x=0x=0,
is increasing when x>0x>0x>0.
In simple words:
The graph goes down until it reaches the vertex, and then it goes up.
For:
y=−x2y=-x^2y=−x2
the opposite happens:
the graph goes up until it reaches the vertex,
then it goes down.
A parabola can have a minimum or a maximum.
If it opens upwards, it has a minimum.
Example:
y=x2+1y=x^2+1y=x2+1
The vertex is (0,1)(0,1)(0,1), so the minimum value is:
y=1y=1y=1
If it opens downwards, it has a maximum.
Example:
y=−x2+4y=-x^2+4y=−x2+4
The vertex is (0,4)(0,4)(0,4), so the maximum value is:
y=4y=4y=4
A parabola is the graph of a quadratic function.
Important ideas:
Concept
Meaning
Vertex
The turning point of the parabola
Axis of symmetry
The vertical line that divides the parabola into two equal halves
Opens upwards
The parabola has a minimum
Opens downwards
The parabola has a maximum
Y-intercept
Point where the graph crosses the y-axis
X-intercepts
Points where the graph crosses the x-axis
Study the function:
y=x2−3y=x^2-3y=x2−3
The parabola opens upwards because the coefficient of x2x^2x2 is positive.
The vertex is:
(0,−3)(0,-3)(0,−3)
The y-intercept is:
(0,−3)(0,-3)(0,−3)
To find the x-intercepts:
0=x2−30=x^2-30=x2−3 x2=3x^2=3x2=3
So the graph crosses the x-axis approximately at:
x=−1.7x=-1.7x=−1.7
and
x=1.7x=1.7x=1.7
Study the function:
y=−x2+5y=-x^2+5y=−x2+5
The parabola opens downwards because the coefficient of x2x^2x2 is negative.
The vertex is:
(0,5)(0,5)(0,5)
The maximum value is:
y=5y=5y=5
The y-intercept is:
(0,5)(0,5)(0,5)
To find the x-intercepts:
0=−x2+50=-x^2+50=−x2+5 x2=5x^2=5x2=5
So the graph crosses the x-axis approximately at:
x=−2.2x=-2.2x=−2.2
and
x=2.2x=2.2x=2.2
Complete the table for:
y=x2−1y=x^2-1y=x2−1
xxx
y=x2−1y=x^2-1y=x2−1
-3
-2
-1
0
1
2
3
Then draw the graph.
For each function, say whether the parabola opens upwards or downwards.
a)
y=x2+2y=x^2+2y=x2+2
b)
y=−x2+3y=-x^2+3y=−x2+3
c)
y=4x2y=4x^2y=4x2
d)
y=−0.5x2−1y=-0.5x^2-1y=−0.5x2−1
Find the vertex of each parabola.
a)
y=x2+6y=x^2+6y=x2+6
b)
y=x2−4y=x^2-4y=x2−4
c)
y=−x2+2y=-x^2+2y=−x2+2
d)
y=−x2−3y=-x^2-3y=−x2−3
Find the y-intercept of each function.
a)
y=x2+7y=x^2+7y=x2+7
b)
y=x2−5y=x^2-5y=x2−5
c)
y=−x2+1y=-x^2+1y=−x2+1
d)
y=−x2−4y=-x^2-4y=−x2−4
Find the x-intercepts.
a)
y=x2−9y=x^2-9y=x2−9
b)
y=x2−1y=x^2-1y=x2−1
c)
y=−x2+4y=-x^2+4y=−x2+4
d)
y=x2+3y=x^2+3y=x2+3
A basketball player throws a ball. The height of the ball can be modelled by this function:
h=−x2+6xh=-x^2+6xh=−x2+6x
where:
xxx is the horizontal distance in metres,
hhh is the height of the ball in metres.
Answer the questions:
Does the parabola open upwards or downwards?
What does this tell us about the movement of the ball?
Complete the table:
xxx
h=−x2+6xh=-x^2+6xh=−x2+6x
0
1
2
3
4
5
6
What is the maximum height of the ball?
At what distance does the ball touch the ground again?
A parabola is not just a curve. It tells a story.
It can show:
something going up and down,
a maximum height,
a minimum value,
symmetry,
movement,
growth and decrease.
The most important point of a parabola is the vertex, because it tells us where the graph changes direction.