2005

Q1

s = (b distance travelled at top speed) + (b distance to stop) - (a distance to stop)

s = ut

50m

400 = -6s

s = 66.67

a

u = 20 v = 0 a = -6

U2 = -2as

400 = -12s

s = 33.33

50 + 66.67 - 33.33 = 83.33 m