Ввести Y/N

char charValue, NL;

printf("<Please enter a character>: ");

clearKeyboard();

scanf("%c%c", &charValue, &NL);

while ((charValue != 'Y' && charValue != 'y' && charValue != 'N' && charValue != 'n') ||

          (NL != '\n'))

{

     printf("*** INVALID ENTRY *** <Only (Y)es or (N)o are acceptable>: ");

     clearKeyboard();

     scanf("%c%c", &charValue, &NL);

}

if (charValue == 'Y' || charValue == 'y')

{

     return 1;

}

else

{

     return 0;

}

void clearKeyboard()

{

while (getchar() != '\n');

}