Ввести Y/N
char charValue, NL;
printf("<Please enter a character>: ");
clearKeyboard();
scanf("%c%c", &charValue, &NL);
while ((charValue != 'Y' && charValue != 'y' && charValue != 'N' && charValue != 'n') ||
(NL != '\n'))
{
printf("*** INVALID ENTRY *** <Only (Y)es or (N)o are acceptable>: ");
clearKeyboard();
scanf("%c%c", &charValue, &NL);
}
if (charValue == 'Y' || charValue == 'y')
{
return 1;
}
else
{
return 0;
}
void clearKeyboard()
{
while (getchar() != '\n');
}