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Cliff Problem Quizlette
Red Elk runs at a speed of 9.20 m/s horizontally off a cliff that is 6.40 m above the water.
A) Set up your horizontal/vertical table, fill it with known quantities, and solve for everything you don’t know. (You know horizontally: both velocities and the acceleration, and vertically: the displacement, the initial velocity, and the acceleration)
B) What time is he in the air?
(1.14 s)
C) What is his final vertical velocity of impact? (-11.2 m/s)
D) How far from the base of the cliff does he hit the water?
(10.5 m)
F) What is his speed of impact with the water? (14.5 m/s)
E) Draw a picture of his velocity of impact, and turn it into an angle-magnitude velocity vector. Find the angle with the horizontal, and label both the angle and the magnitude. (14.5 m/s, 50.6o below horiz)
Red Elk runs at a speed of 9.20 m/s horizontally off a cliff that is 6.40 m above the water.
When Red Elk is 3.1 m above the water, inspiration strikes him. (set up another H|V table and solve)
· What is Red Elk’s position (relative to the cliff edge) when he is 3.10 m above the water? (how far over, how far down from the edge) (7.55 m over, -3.30 m down)
· What is Red Elk’s velocity in Vector Components and Angle Magnitude (draw a picture) notation when he is 3.1 m above the water? (9.20 m/s x + -8.05 m/s y, 12.2 m/s 41.2o below horiz)
What is Red Elk’s position (VC notation relative to the cliff edge) and Velocity (VC and AM - draw a picture) at 0.50 seconds after leaving the edge of the cliff?
(4.60 m over, -1.23 (down), 9.20 m/s x + -4.905 m/s y, 10.4 m/s 28.1o below horiz)
What is Red Elk’s position (VC notation relative to the cliff edge) and Velocity (VC and AM - draw a picture) when he has covered 8.0 horizontal meters of distance?
(8.00 m over, -3.71 m down, 9.20 m/s x + -8.53 m/s y, 12.5 m/s 42.8o below horiz)
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