RC Circuit Lab

Get the Lab Handout: Lab-RC Circuits.pdf

The Directions in the lab:

RC Circuits

Ohm's Law states that the rate at which charge flows is proportional to the voltage making the charge flow. Here we are going to look at the voltage across a capacitor as it discharges through a resistor.

Gathering the data:

1. Open the file "RC Circuit Lab" on the desktop. When a window pops up asking about a voltage sensor, click "Connect".

2. From the "Experiment" menu choose "Data Collection"

3. Click the "Collection" tab and have it collect one sample per second for about 3 time constants. (The resistor is a 1 MΩ, so 1.0x106 ohms, and the capacitor has its value printed on it, read this, and multiply. τ = RC. Type this into the “Length” box) Record the values of your resistor and your capacitor so you have them later

4. Click the "Triggering" tab and have the experiment automatically start as it decreases across 4.8 V. (Click "Triggering" and “On Sensor Value” and "Decreasing" and type in 4.8 for the value. 0 samples before triggering)

5. Click OK to get rid of the Data Collection dialog box, and click on the last number on the time axis of the graph and change it to the length of the experiment you set in step 3 (If it doesn’t change for you)

6. Hold the orange wire to the side of the capacitor that has the red connector attached to it. Notice that the voltage goes up to 4.981 V. Press the "Collect" button, and wait until you see that it is waiting to trigger.

7. Disconnect the orange wire from the side of the capacitor. It will start to drain. The data collection should start automatically when the voltage falls across the threshold you set in step 4 (4.8 V?) Typically the first voltage recorded is around 4.77 V

8. When the data collection is finished, right click the upper left corner of the data table, choose "copy", and paste it into a Google Docs spreadsheet, so that you can free up the RC lab setup. You can now do the rest of the write up at home, or here on your own device.

Writing up the lab:

1. Make a nice labeled graph of your data. One time constant is when the voltage falls to e-1 times the original voltage. (≈ 36.8% of the original voltage) Draw a horizontal line where this is on your graph printout so it intersects your data, and from the intersection of this line and your points of data, draw a line straight down to your x axis. Why does the voltage drop the way it does? Why is it steep at first, and less steep at the end?

2. Look in your data and find at what time the voltage fell to 0.368 (e-1) of the original voltage. (Multiply the first voltage recorded by 0.368, and find at what time it occurs in your data) How does it compare to the time constant you would calculate from the resistor? (Calculate RC, and compare it to the time you looked up)

3. Vo is the first voltage you recorded. Pick 5 ordered pairs of (time, Voltage) throughout your data, and plug them into the formula , and solve for the time constant τ. Do the values of the time constant remain, oh, I don't know.... constant???? Talk about this. Do they show any pattern, or do they just randomly differ?



The write up:

You will print out the graph from a PC in the back of the room. You don't need to print out all your data (please don't). Feel free to write your answers to the questions right on the sheet of paper your graph is on.

0. How to get the data:


1. Making a graph, drawing a line, etc.

Make the graph in Sheets, put it on its own page, add gridlines, and print it from a PC in the back of the room (Log into your drive. You can write the answers to the rest of the lab on the sheet of paper the graph is on.

1.1. Answering the question "Why does the voltage drop off the way it does, why is it steep at first, and less steep later?

The rate at which charge flows off the capacitor is proportional to the voltage on the capacitor. When there is a big voltage across the capacitor, there is a big current, and when the voltage is less, there is a smaller current. (An inverse exponential is a curve that has a negative slope that is proportional to its height. - because the derivative of e^(-kt) is -ke^(-kt), right?)

Another way of thinking about it is that it is like air rushing out of a compressed air tank - at first the pressure is high, and the air comes out quickly, and later, the pressure is lower, and the air moves more slowly out of the tank.

Use these ideas in your own words to explain hos the steepness of the graph changes with time.

2. Finding the time constant in your data, calculating your own, comparing.

You don't need to print out your data, just write your answer to the question on the same sheet of paper your graph is on. I typed my answers on the spreadsheet only because I was in blue pen land

Calculating the Time constant 5 times and talking about this:

Don't watch the entire thing - I am pretty sure it is chloroform in digital format. Do go to the end where I discuss how to analyze the patterns in the calculated time constants. Show at least one calculation of the time constants, but calculate all 5.