9.1 - Translational Equilibrium

Get the assessment: FA9.1.docx

Get more practice Problems: Worksheet-Practice9.1.docx

The Assessment Solved:

1. Find the Equilibrant (The third force that would cause translational equilibrium) – express it as an angle magnitude vector. Draw it with its tail on the origin, and label its magnitude, and an angle with one of the axes. Write your answer with 3 sig figs, but carry at least 4 so you don’t make rounding errors.

(32.4 N, at 270.8^o Trig Angle, 0.8^o to the right of the -y axis) - Watch the video to grade your FA

Using Trig Angles

Sleepery Sleepertons: (More chances to be bored with the same sort of problem:)

FA9 1 #1b - I use equilibrium equations to solve these

FA9 1 #1c

2. Find the tensions in the cables C and D. Set up your x and y equations where indicated and solve.

(C = 192 N, D = 285 N)

More boring examples of the same monotonous stuff:

FA9 1 #2a - Another example using matrices

FA9 1 #2b - Symmetry, so it's solvable without matrices

FA9 1 #2c - Another example of solvable without matrices

More Practice Problems:

Translational Equilibrium 9.1

1. Find the third force (the equilibrant) that would prevent the system from accelerating. 23.16 N At 292.8^o Trig angle. (22.8^o to the right of the -y axis)

2. Find the third force (the equilibrant) that would prevent the system from accelerating. 6.000 N At 348.9^o Trig angle. (11.1^o below the +x axis)

3. Find the third force (the equilibrant) that would prevent the system from accelerating. 56.4 N @ 318.8^o Trig angle. (41.2^o below the +x axis)

4. Cable A makes an angle of 63.0^o with the horizontal, and B makes an angle of 23.0^o with the horizontal. What is the tension in each cable for there to be no acceleration of the system?

A = 606 N

B = 299 N