Problems

DAY 1

• A) What is the volume if 10 ml of 6 N base is added to 3 N acid?

• CAVA=CBVB

• 3N(VA)= 6N(10ml)

• VA=20 ml

• B) What is the concentration if 50 ml of .4 N base is added to 10 ml of acid?

• CAVA=CBVB

• (CA) 10 ml = .4 N(50ml)

• CA= 2 N

• C) What is the volume if 20 ml of 1 M base is added to 3 M acid?

• CAVA=CBVB

• 3 M(VA)= 1 M(20ml)

• VA=6.67 ml

• D) What is the concentration if 5 ml of 3 m acid is added to 10 ml of base?

• CAVA=CBVB

• (CA) 10 ml = 3 m(5 ml)

• CA= 1.5 m

DAY 2

• A) What is the volume if 1 L of 2 N base is added to 4 N acid?

• CAVA=CBVB

• 4N(VA)= 2N(1L)

• VA=.5 L

• B) What is the concentration if 50 ml of 2 N base is added to 10 ml of acid?

• CAVA=CBVB

• (CA) 10 ml = 2 N(50ml)

• CA= 10 N

• C) What is the volume if 20 cm3 of 5 M base is added to 2.5 M acid?

• CAVA=CBVB

• 2.5 M(VA)= 5 M(20 cm3)

• VA=40 cm3

• D) What is the concentration if 8 ml of 2 m acid is added to 16 ml of base?

• CAVA=CBVB

• (CA) 16 ml = 2 m(8 ml)

• CA= 1 m

DAY 3

• A) What is the volume if .5 L of 4 N base is added to 2 N acid?

• CAVA=CBVB

• 2N(VA)= 4 N(.5 L)

• VA=1 L

• B) What is the concentration if 100 ml of 1 N base is added to 10 ml of acid?

• CAVA=CBVB

• (CA) 10 ml = 1 N(100ml)

• CA= 10 N

• C) What is the volume if 500 cm3 of 2 M base is added to 2.5 M acid?

• CAVA=CBVB

• 2.5 M(VA)= 2 M(500 cm3)

• VA=400 cm3

• D) What is the concentration if 5 ml of 2 m acid is added to base that started at 16 ml and ended at 6 ml?

• CAVA=CBVB

• 16-6 = 10 ml

• (CA) 10 ml = 2 m(5 ml)

• CA= 1 m

DAY 4

• A) What is the volume if 20 cm3 of 2 N base is added to .5 N acid?

• CAVA=CBVB

• .5 N(VA)= 2 N(20 cm3 )

• VA= 80 cm3

• B) What is the concentration if 50 ml of 6 N base is added to 10 ml of acid?

• CAVA=CBVB

• (CA) 10 ml = 6 N(50ml)

• CA= 30 N

• C) What is the volume if 1000 cm3 of 1 M base is added to 5 M acid?

• CAVA=CBVB

• 5 M(VA)= 1 M(1000 cm3)

• VA=200 cm3

• D) What is the concentration if 10 ml of 2 m acid is added to base that started at 50 ml and ended at 10 ml?

• Calculate volume added. 50-10=40 ml

• CAVA=CBVB

• 2 m (10 ml) = CB(40 ml)

• CB= .5 m

DAY 5

• A) What is the concentration of the base that was drained from 23 ml to 18 ml and added to a 3 M acid that started at 32 ml and ended at 22 ml?

• CBVB=CAVA

• 23-18= 5 32-22= 10

• CB (5 ml) =3 M(10 ml)

• CB= 6 M

• B) What is the concentration of the base that was drained from 22 ml and ended at 42 ml and added to a 10 N acid that started at 100 ml and ended at 20 ml?

• CBVB=CAVA

• 42-22= 20 100-20= 80

• CB (20 ml) =10 N(80 ml)

• CB= 40 N

• C) What is the volume if 500 cm3 of 2 M base is added to 10 M acid?

• CAVA=CBVB

• 10 M(VA)= 2 M(500 cm3)

• VA= 100 cm3

• D) What is the concentration if 20 ml of 2 m acid is added to base that started at 16 ml and ended at 6 ml?

• CBVB=CAVA

• 16-6=10 ml of base

• (CB) 10 ml = 2 m(20 ml)

• CB= 4 m

DAY 6

• A) What is the concentration of the base that was drained from 8 ml to 18 ml and added to a 2 M acid that started at 42 ml and ended at 22 ml?

• CAVA=CBVB

• 18-8= 10 42-22= 20

• CA (10 ml) =2 M(20 ml)

• CA= 4 M

• B) What is the concentration of the base that was drained from 22 ml and ended at 47 ml and added to a 5 N acid that started at 70 ml and ended at 20 ml?

• CBVB=CAVA

• 47-22= 25 70-20= 50

• CB (25 ml) =5 N(50 ml)

• CB= 10 N

• C) What is the volume if 500 cm3 of .5 M base is added to 1 M acid?

• CAVA=CBVB

• 1 M(VA)= .5 M(500 cm3)

• VA= 250 cm3

• D) What is the concentration if 20 ml of .2 m acid is added to base that started at 26 ml and ended at 6 ml?

• CBVB=CAVA

• (CB) 20 ml = .2 m(20 ml)

• CB= .2 m

DAY 7

• A) What is the concentration of the base that was drained from 12 ml to 18 ml and added to a 3 M acid that started at 40 ml and ended at 22 ml?

• CAVA=CBVB

• 18-12= 6 40-22= 18

• CA (6 ml) =3 M(18 ml)

• CA= 9 M

• B) What is the concentration of the base that was drained from 40 ml and ended at 47 ml and added to a 2 N acid that started at 48 ml and ended at 20 ml?

• CBVB=CAVA

• 47-40= 7 48-20= 28

• CB (7 ml) =2 N(28 ml)

• CB= 8 N

• C) What is the volume if 500 cm3 of 2.5 M base is added to 1 M acid?

• CAVA=CBVB

• 1 M(VA)= 2.5 M(500 cm3)

• VA= 1250 cm3

• D) What is the concentration if 20 ml of .05 m acid is added to base that started at 26 ml and ended at 21 ml?

• CBVB=CAVA

• (CB) 5 ml = .05 m(20 ml)

• CB= .2 m

DAY 8

• A) What is the volume if 1 L of 8 N base is added to 4 N acid?

• CAVA=CBVB

• 4N(VA)= 8N(1L)

• VA= 2 L

• B) What is the concentration if 50 ml of 2 m base is added to 100 ml of acid?

• CAVA=CBVB

• (CA) 100 ml = 2 m(50ml)

• CA= 1 m

• C) What is the volume if 12 L of 5 M base is added to 3 M acid?

• CAVA=CBVB

• 3 M(VA)= 5 M(12 L)

• VA= 20 L

• D) What is the concentration if 20 ml of .6 m acid is added to base that started at 26 ml and ended at 20 ml?

• CBVB=CAVA

• (CB) 6 ml = .6 m(20 ml)

• CB= 2 m

DAY 1

• A) What is the volume if 10 ml of 6 N base is added to 3 N acid?

• CAVA=CBVB

• 3N(VA)= 6N(10ml)

• VA=20 ml

• B) What is the concentration if 50 ml of .4 N base is added to 10 ml of acid?

• CAVA=CBVB

• (CA) 10 ml = .4 N(50ml)

• CA= 2 N

• C) What is the volume if 20 ml of 1 M base is added to 3 M acid?

• CAVA=CBVB

• 3 M(VA)= 1 M(20ml)

• VA=6.67 ml

• D) What is the concentration if 5 ml of 3 m acid is added to 10 ml of base?

• CAVA=CBVB

• (CA) 10 ml = 3 m(5 ml)

• CA= 1.5 m

DAY 2

• A) What is the volume if 1 L of 2 N base is added to 4 N acid?

• CAVA=CBVB

• 4N(VA)= 2N(1L)

• VA=.5 L

• B) What is the concentration if 50 ml of 2 N base is added to 10 ml of acid?

• CAVA=CBVB

• (CA) 10 ml = 2 N(50ml)

• CA= 10 N

• C) What is the volume if 20 cm3 of 5 M base is added to 2.5 M acid?

• CAVA=CBVB

• 2.5 M(VA)= 5 M(20 cm3)

• VA=40 cm3

• D) What is the concentration if 8 ml of 2 m acid is added to 16 ml of base?

• CAVA=CBVB

• (CA) 16 ml = 2 m(8 ml)

• CA= 1 m

DAY 3

• A) What is the volume if .5 L of 4 N base is added to 2 N acid?

• CAVA=CBVB

• 2N(VA)= 4 N(.5 L)

• VA=1 L

• B) What is the concentration if 100 ml of 1 N base is added to 10 ml of acid?

• CAVA=CBVB

• (CA) 10 ml = 1 N(100ml)

• CA= 10 N

• C) What is the volume if 500 cm3 of 2 M base is added to 2.5 M acid?

• CAVA=CBVB

• 2.5 M(VA)= 2 M(500 cm3)

• VA=400 cm3

• D) What is the concentration if 5 ml of 2 m acid is added to base that started at 16 ml and ended at 6 ml?

• CAVA=CBVB

• 16-6 = 10 ml

• (CA) 10 ml = 2 m(5 ml)

• CA= 1 m

DAY 4

• A) What is the volume if 20 cm3 of 2 N base is added to .5 N acid?

• CAVA=CBVB

• .5 N(VA)= 2 N(20 cm3 )

• VA= 80 cm3

• B) What is the concentration if 50 ml of 6 N base is added to 10 ml of acid?

• CAVA=CBVB

• (CA) 10 ml = 6 N(50ml)

• CA= 30 N

• C) What is the volume if 1000 cm3 of 1 M base is added to 5 M acid?

• CAVA=CBVB

• 5 M(VA)= 1 M(1000 cm3)

• VA=200 cm3

• D) What is the concentration if 10 ml of 2 m acid is added to base that started at 50 ml and ended at 10 ml?

• Calculate volume added. 50-10=40 ml

• CAVA=CBVB

• 2 m (10 ml) = CB(40 ml)

• CB= .5 m

DAY 5

• A) What is the concentration of the base that was drained from 23 ml to 18 ml and added to a 3 M acid that started at 32 ml and ended at 22 ml?

• CBVB=CAVA

• 23-18= 5 32-22= 10

• CB (5 ml) =3 M(10 ml)

• CB= 6 M

• B) What is the concentration of the base that was drained from 22 ml and ended at 42 ml and added to a 10 N acid that started at 100 ml and ended at 20 ml?

• CBVB=CAVA

• 42-22= 20 100-20= 80

• CB (20 ml) =10 N(80 ml)

• CB= 40 N

• C) What is the volume if 500 cm3 of 2 M base is added to 10 M acid?

• CAVA=CBVB

• 10 M(VA)= 2 M(500 cm3)

• VA= 100 cm3

• D) What is the concentration if 20 ml of 2 m acid is added to base that started at 16 ml and ended at 6 ml?

• CBVB=CAVA

• 16-6=10 ml of base

• (CB) 10 ml = 2 m(20 ml)

• CB= 4 m

DAY 6

• A) What is the concentration of the base that was drained from 8 ml to 18 ml and added to a 2 M acid that started at 42 ml and ended at 22 ml?

• CAVA=CBVB

• 18-8= 10 42-22= 20

• CA (10 ml) =2 M(20 ml)

• CA= 4 M

• B) What is the concentration of the base that was drained from 22 ml and ended at 47 ml and added to a 5 N acid that started at 70 ml and ended at 20 ml?

• CBVB=CAVA

• 47-22= 25 70-20= 50

• CB (25 ml) =5 N(50 ml)

• CB= 10 N

• C) What is the volume if 500 cm3 of .5 M base is added to 1 M acid?

• CAVA=CBVB

• 1 M(VA)= .5 M(500 cm3)

• VA= 250 cm3

• D) What is the concentration if 20 ml of .2 m acid is added to base that started at 26 ml and ended at 6 ml?

• CBVB=CAVA

• (CB) 20 ml = .2 m(20 ml)

• CB= .2 m

DAY 7

• A) What is the concentration of the base that was drained from 12 ml to 18 ml and added to a 3 M acid that started at 40 ml and ended at 22 ml?

• CAVA=CBVB

• 18-12= 6 40-22= 18

• CA (6 ml) =3 M(18 ml)

• CA= 9 M

• B) What is the concentration of the base that was drained from 40 ml and ended at 47 ml and added to a 2 N acid that started at 48 ml and ended at 20 ml?

• CBVB=CAVA

• 47-40= 7 48-20= 28

• CB (7 ml) =2 N(28 ml)

• CB= 8 N

• C) What is the volume if 500 cm3 of 2.5 M base is added to 1 M acid?

• CAVA=CBVB

• 1 M(VA)= 2.5 M(500 cm3)

• VA= 1250 cm3

• D) What is the concentration if 20 ml of .05 m acid is added to base that started at 26 ml and ended at 21 ml?

• CBVB=CAVA

• (CB) 5 ml = .05 m(20 ml)

• CB= .2 m

DAY 8

• A) What is the volume if 1 L of 8 N base is added to 4 N acid?

• CAVA=CBVB

• 4N(VA)= 8N(1L)

• VA= 2 L

• B) What is the concentration if 50 ml of 2 m base is added to 100 ml of acid?

• CAVA=CBVB

• (CA) 100 ml = 2 m(50ml)

• CA= 1 m

• C) What is the volume if 12 L of 5 M base is added to 3 M acid?

• CAVA=CBVB

• 3 M(VA)= 5 M(12 L)

• VA= 20 L

• D) What is the concentration if 20 ml of .6 m acid is added to base that started at 26 ml and ended at 20 ml?

• CBVB=CAVA

• (CB) 6 ml = .6 m(20 ml)

• CB= 2 m

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