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[1] Wheatstone bridge/Resistance bridge/Bridge circuit is a seriesparallel circuit, with 4 resistors connected to give a null center value--no current flows through it if its resistances ratio is equal.
It precisely measure an unknown resistance by balancing its 2 legs, where one has the unknown resistor; when bridge is balanced, voltage across center point = zero, for accurate calculation of the unknown resistance based on the values of its other known resistors.
Usually, the bridge is unbalanced where current flows through the galvanometer and is balanced if no current flows through it, which is done by alterong the known resistance and variable resistance.
[6] Examples
[6] Examples
This circuit has the same ratio between resistor 5 and 10, and 1 and 2: 5:10 and 1:2, which is a balanced network.
Since it's balanced, no current goes into 6 Ω resistor, whose current is 0, as if the resistor isn't there. Without it 6 Ω resistor, other resistors are now in paralel and can be solved.
This is unbalanced since R1:R2 = 3:1 and R4:R5 = 6:5.
Note: Arrows shows where the points are between the 2 different forms of the same circuit.
The left circuit isn't a Wheatstone circuit since its middle resistor (1 Ω) is connected to the battery path (vertical in this case) is (pointed by red arrows).
Note: Arrows points where the same points are between the 2 forms of the same circuit.
If 1 Ω was at where the battery path isn't at (horizontal in this case), then it's a Wheatstone circuit, 1 Ω has no current, and other resistors are in parallel.
If 5 Ω has x volts, so does 1 Ω.
If 10 Ω has 2x volts, so does 6 Ω.
9 must be divided in the ratio 1:2.
As 9 divides into 1:2, one part gets 1/3 and another gets 2/3.
5 and 1 Ω resistor have 3 V (has 1/3)
10 and 2 Ω resistors have 6 V (has 2/3).
Opposite points also have the same voltages as shown, therefore no current flows in a balanced Wheatstone circuit's middle circuit (6 Ω in this case).
Example 1
Example 1
Find the "? resistor" resistance.
We can replace the center resistor with a galvanometer (G), which detects current.
We can take any of the resistors (2 Ω resistor in this case) as a variable resistor.
Change the variable resistor til the galvanometer hits 0 where the resistor changes to 7 V, in this case.
If the current in the middle is 0, the circuit is balanced,
so, if ratio here is 1:7, then "? resistance" is 5x7 = 35 Ω =.
[1] Derivation
[1] Derivation
History
History
Wheatstone circuits was developed by Charles Wheatstone
References
References
[2]
[3]
[4] The Different Types of Electrical Circuits and Their Uses - Titan
[6] Wheatstone bridge & its logic | Electric current | Physics | Khan Academy - YT
Quizzes
Quizzes
[Q2] Basic Electronic Exercises - Teach Me To Make (no answers)
[Q3] Circuit components quiz
[Q4] Parallel circuits
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