An eccentric salesman arrives at your lab peddling what he claims is an extraordinarily rare and dense "Elixir Oil," sold by weight at an exorbitant price. He places a beaker filled with this shimmering oil onto a sensitive digital scale, proudly announcing its initial weight.
Before finalizing the price, he insists on checking the oil's "consistency" with his own special silver spoon. He carefully lowers the spoon into the oil, holding it steady so it is submerged but not touching the bottom or sides of the beaker. You, a keen physics student, observe that the reading on the digital scale increases the moment the spoon enters the oil and remains higher while he holds it there.
Your Task:
Analyze this situation using your understanding of fluid principles and forces.
Explain the Observation:
Explain what happens to the value of the scale reading.
Suppose the spoon was supported by light spring, would the spring lengthen, shorten or remain the same length? Use physics principles to justify your explanation.
Free-Body Diagrams: Draw clear free-body diagrams for:
The beaker of oil (while the spoon is submerged).
The spoon (while submerged in the oil and held by the salesman/spring). Label all relevant forces (e.g., gravitational force, buoyant force, normal force, applied force from the hand, etc.). Ensure your diagrams illustrate Newton's Third Law pairs where appropriate between the spoon and the fluid.
Quantify the Change: Let the density of the "Elixir Oil" be ρ and the volume of the spoon submerged in the oil be V. Derive an expression for the increase in the force measured by the scale in terms of ρ, V, and g (the acceleration due to gravity).
The Sales Pitch:
Does this demonstration provide any valid scientific evidence for the oil being particularly dense or having special properties?
Does the type of spoon (e.g., silver) matter in this context? Explain why or why not from a physics perspective.
Go to the explore option and take three minutes to play with the options.
Make sure to turn on the forces so you can see them
Can you find multiple ways to increase the buoyant force?
What role does fluid density play?
Now, we will collect data. Our goal to explore two relationships:
Buoyant force & volume of water displaced
Keep water density & gravitational acceleration constant
Buoyant force & the density of the liquid
Keep volume of water displaced & gravitational acceleration constant
Adapted from K. Doyle Crossman
All of the animals shown have the same mass and are at rest. What will their free body diagrams look like? Discuss.
Density, ρ, is a measurement of an object’s mass, m, divided by its volume, V. The greater the density, the greater the concentration of mass within the object.
Density is a scalar quantity and has the units of
kg/m3 (or equivalently, kg•m−3)
This is because the units of mass are kg and the units of volume are m3.
3 Quick Problems:
A solid, uniform cube has a side length of 0.50 m and a mass of 250 kg.
Calculate the density of the material the cube is made from. ρ=V/m=0.125 m3/250 kg=2000 kg/m3
An irregularly shaped piece of metal has a mass of 135 g. When submerged completely in a graduated cylinder initially containing 50.0 mL of water, the water level rises to 65.0 mL.
Calculate the volume of the metal piece in cm³. Vmetal=15.0 cm3
Calculate the density of the metal in g/cm³. ρ=9 g/cm3
Convert the density to kg/m³. (Note: 1 g/cm³=1000 kg/m³) ρ=9000 kg/m3
Object A has a mass m and a volume V. Object B has a mass 2m and a volume 3V. Both objects are placed in a large tank of water (density ρw=1000 kg/m3 ).
Express the density of Object A (ρA) and Object B (ρB) in terms of m and V. ρA=V/m. ρB=2V/3m.
Which object is denser? Justify your answer. Object B is less dense than Object A. Object A is denser.
Suppose Object A has a density of 1200 kg/m3 . Will Object A float or sink in the water? Will Object B float or sink in the water? Explain your reasoning based on density comparisons. Object A will sink (ρA=1200kg/m3). Object B will float. ρB=2/3(1200)=800kg/m3)
The force of water or liquid-on-an-object is called buoyant force, FB. The strength of this force is dependant on three factors:
The density, ρ, of the water or liquid, NOT the density of the object
The volume of water displaced, V, NOT the volume of the object.
The acceleration from gravity, g
A solid sphere with a volume of 0.025 m3 is held fully submerged in a freshwater lake (density of water ρw≈1000 kg/m3). Calculate the magnitude of the buoyant force exerted by the water on the sphere. (Use g≈10 m/s2). F_B=250 N
A block of wood has a density of 750 kg/m3. The block is placed in a container of oil with a density of 900 kg/m3.
Will the block float or sink in the oil? Explain. ρwood=750 kg/m3 and ρoil=900 kg/m3. Since ρwood<ρoil, the block will float.
If it floats, what fraction of the wood block's total volume is submerged beneath the surface of the oil? (See Below) 5V_w/6 = 83% V_w
Object X has mass m and volume V. Object Y has mass 2m and volume V. Object Z has mass m and volume 2V. All three objects are fully submerged in the same fluid of density ρf.
Express the buoyant force on each object (FB,X, FB,Y, FB,Z) in terms of ρf, V, and g. FB,X = ρfVg , FB,Y = ρfVg , FB,Z = 2ρfVg
Rank the magnitudes of the buoyant forces on the three objects from largest to smallest. Justify your ranking. F_Bz > F_Bx = F_By
Does the mass of the submerged object directly determine the buoyant force acting on it? Explain. No, the mass of the fully submerged object does not directly determine the buoyant force. The buoyant force depends only on the density of the fluid and the volume of the object that is submerged (which displaces the fluid). Objects X and Y have different masses but experience the same buoyant force because they have the same volume and are in the same fluid. Object Z has the same mass as X but experiences a larger buoyant force because it has a larger volume.
This means that an object will experience its maximum buoyancy once it is fully submerged. Going deeper into the water will not change the buoyant force for the object.
An eccentric salesman arrives at your lab peddling what he claims is an extraordinarily rare and dense "Elixir Oil," sold by weight at an exorbitant price. He places a beaker filled with this shimmering oil onto a sensitive digital scale, proudly announcing its initial weight.
Before finalizing the price, he insists on checking the oil's "consistency" with his own special silver spoon. He carefully lowers the spoon into the oil, holding it steady so it is submerged but not touching the bottom or sides of the beaker. You, a keen physics student, observe that the reading on the digital scale increases the moment the spoon enters the oil and remains higher while he holds it there.
Your Task:
Analyze this situation using your understanding of fluid principles and forces.
Explain the Observation: Why does the scale reading increase even though the spoon is not touching the beaker? Use physics principles to justify your explanation.
Free-Body Diagrams: Draw clear free-body diagrams for:
The beaker of oil (while the spoon is submerged).
The spoon (while submerged in the oil and held by the salesman). Label all relevant forces (e.g., gravitational force, buoyant force, normal force, applied force from the hand, etc.). Ensure your diagrams illustrate Newton's Third Law pairs where appropriate between the spoon and the fluid.
Quantify the Change: Let the density of the "Elixir Oil" be ρ and the volume of the spoon submerged in the oil be V. Derive an expression for the increase in the force measured by the scale in terms of ρ, V, and g (the acceleration due to gravity).
The Sales Pitch: Does this demonstration provide any valid scientific evidence for the oil being particularly dense or having special properties? Does the type of spoon (e.g., silver) matter in this context? Explain why or why not from a physics perspective.
A cup of water (of density 1,000 kg/m3) has a cube floating in it, at rest. The mass of the cube is 8 kg. The total volume of the cube is 0.012 m3.
Draw a free body diagram for the cube in the water.
Calculate the volume of the water displaced by the cube.
Fg = FB mg = ρVg 80 = (1,000)V(10) V = 0.008 m3
If the whole cube is submerged and then released, calculate the cube’s acceleration immediately after release.
FB = ρVg FB = (1,000)(0.012)(10) – 80 FB = 120 N
ΣF = FB – Fg ΣF = 120 – 80 = 40 N
a = ΣF / m a = 40 / 8 = 5 m/s2
The density of water is 1,000 kg/m3.
Object A has a mass of 4 kg and a volume of 0.006 m3.
If it is fully submerged in water, how much buoyant force will it experience?
FB = ρVg FB = (1,000)(0.006)(10) FB = 60 N
Will it float or sink in water?
It will float. It’s buoyant force fully submerged is greater than its weight.
Object B has a mass of 4 kg and a volume of 0.002 m3.
If it is fully submerged in water, how much buoyant force will it experience?
FB = ρVg FB = (1,000)(0.002)(10) FB = 20 N
Will it float or sink in water?
It’ll sink. Its weight is greater than the buoyant force when fully submerged.
Compare the densities of the two objects.