Understandings
Applications and Skills
Guidance
HOWEVER Signals for the H in an O-H bond are not affected by hydrogens on adjacent atoms so are not split
TWO SIGNALS
Quartet and triplet :- ratio of peak areas = 3 : 2
Carbons 1 & 4 are the similar and so are carbons 2 & 3 so there are only two different chemical environments.
The signal for H’s on carbon 2 is a quartet - you ignore the two neighbours on carbon 3 because they are chemically identical.
TWO SIGNALS
both singlets :- ratio of peak areas = 2 : 1
Hydrogens on OH groups only give singlets. The signal for H’s on each carbon are not split, because
- H’s on the neighbouring carbon are chemically
identical... and
- H’s on adjacent OH groups do not couple.
An nmr spectrum provides several types of information :-
In many cases this information is sufficient to deduce the structure of an organic molecule but other forms of spectroscopy are used in conjunction with nmr.
1. Get the formula of the compound
2. Draw out the structure
3. Go to each atom in turn and ask the ‘census’ questions
4. Work out what the spectrum would look like ... signals due to H’s nearer electronegative atoms (Cl,Br,O) are shifted downfield to higher d values
3 environments = 3 signals
Triplet d = 3.4
Sextet d = 1.9
Triplet d = 1.0
Signal for H’s on carbon 3 is shifted furthest downfield from TMS due to proximity of the electronegative halogen
Area ratio from relative heights of integration lines = 2 : 2 : 3
Carbon 1 3
Carbon 2 2
Carbon 3 2
Chemically different hydrogen atoms on adjacent atoms = 2
2 + 1 = 3
The signal will be a
TRIPLET
Chemically different hydrogen atoms on adjacent atoms = 5
5 + 1 = 6
The signal will be a
SEXTET
Chemically different hydrogen atoms on adjacent atoms = 2
2 + 1 = 3
The signal will be a
TRIPLET
The signal is shifted furthest away (downfield) from TMS as the hydrogen atoms are nearest the electronegative bromine atom.