Determine the formula of an ionic compound from the charges on the ions present
Use the symbols of the elements and write the formulae of simple compounds
Group 1 (Alkali Metals) have 1 electron in their outer shell. It is easy for them to lose this electron to become a 1+ cation.
Group 2 (Alkaline Earth Metals) have 2 electrons in their outer shell. It is easy for them to lose these electrons to become a 2+ cation
Group 7 (Halogens) have 7 electrons in their outer shell. It is easy for them to gain one electron to become a 1- anion.
Group 6 (Chalcogens) have 6 electrons in their outer shell. It is easy for them to gain two electrons to become a 2- anion.
These are made of several atoms bonded together. You need to memorise the names and formulae of these polyatomic ions
Carbonate ion, CO32-
Sulfate ion, SO42-
Ammonium ion, NH4+
Hydroxide ion, OH-
Nitrate ion, NO3-
Many (but not all) transition metals can form cations with different charges. For example, iron can produce cations with a charge of +2 or +3. Copper can produce cations with a charge of +1, +2, or +3.
If the metal in an ionic compound can form different cations, we identify the cation present by including its charge using Roman numerals in brackets
E.g. iron (III) chloride = made of Fe3+ and Cl-
iron (II) oxide = made of Fe2+ and O2-