Al+3(aq) = Al(H2O)6+3
Al+3(aq) + 6H2O → Al(H2O)6+3
Al(H2O)6+3(aq) + H2O(l) ⇋ Al(H2O)5(OH)+2(aq) + H3O+(aq)
As with other polyprotic acids, the hydrated aluminum ion ionizes in stages, as shown by:
Al(H2O)6+3(aq) + H2O(l) ⇋ Al(H2O)5(OH)+2(aq) + H3O+(aq)
Al(H2O)5(OH)+2(aq) + H2O(l) ⇋ Al(H2O)4(OH)2+1(aq) + H3O+(aq)
Al(H2O)4(OH)2+1(aq) + H2O(l) ⇋ Al(H2O)3(OH)3(s) + H3O+(aq)
As you can see in each stage the Hydrated ion Loses 1 water and gains a hydroxide - in actual fact the water loses a proton
Also - Note that some of these aluminum species are exhibiting amphiprotic behavior, since they are acting as acids when they appear on the left side of the equilibrium expressions and as bases when they appear on the right side.
However, the ionization of a cation carrying more than one charge is usually not extensive beyond the first stage.
This means we can compare the Ka of the first stages of ionisation of different transition metal complexes to compare their relative acid strength.
+3 ions have a stronger effect on water then +2 ions so +3 ions are more acidic this is because the Central metal ion has a stronger polarising effect on the water - making it easier for a Proton to be released.
The key learning points here are that: