Step 1: Balance the equation for the formation of the PPT
Ag+(aq) + Br-(aq) → AgBr(s)
Step 2: Calculate moles of the AgNO3 used using C x (V/1000)
(18.73/1000) x 0.1 = 0.001873 moles
Step 3: Calculate moles of the AgBr in the sample (hence the moles of the Bromide ion)
1:1 ratio so Br- = 0.001873 moles
Step 4: Calculate the concentration of the Br- in the sample using moles/(volume/1000)
0.001873/(25/1000) = 0.07492 molL-1