Embedded Files
while(t != 0)
{
reverse = reverse * 10;
reverse = reverse + t%10;
t = t/10;
if (n == reverse)
printf("Palindrome\n");
else
printf("Not Palindrome\n");
}
// Input:
// Output:
//0, 1, 2, 3, 4, 5, 6, 7, 8, 9,11, 22, 33, 44, 55, 66, 77, 88, 99, 111, 121 etc.
The given code is used to determine whether a given number is a palindrome or not. A palindrome number is a number that remains the same when its digits are reversed. For example, 121, 1221, and 12321 are palindrome numbers.
Here is a breakdown of the logic in the code:
1. The code snippet is part of a larger program and assumes the existence of a variable `t` representing the input number.
2. The `reverse` variable is initialized to 0. This variable will store the reverse of the input number.
3. The code enters a while loop that continues until the input number `t` becomes 0. The purpose of this loop is to reverse the digits of the number.
4. Inside the loop, the `reverse` variable is multiplied by 10 and then the remainder of `t` divided by 10 is added to it. This operation effectively shifts the existing digits in `reverse` to the left by one place and adds the last digit of `t` to the right side.
5. The value of `t` is updated by dividing it by 10, effectively removing the last digit from `t`.
6. After each iteration of the loop, the code checks if the original input number `n` is equal to the reversed number `reverse`. If they are equal, it means the number is a palindrome.
7. If the numbers are equal, the code prints "Palindrome". Otherwise, it prints "Not Palindrome".
The expected input for this code is a positive integer. If the input number is a palindrome, the output will be "Palindrome". Otherwise, it will be "Not Palindrome". The code works by reversing the digits of the number and comparing it to the original number. If they match, it is a palindrome. Otherwise, it is not.
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