int main ()
{
char *a[2] = {"hello", "hi"};
printf("%s", *(a+1));
return 0;
}
Output
hi
Description
This code snippet demonstrates the use of arrays of pointers to characters. Here's a breakdown of what's happening in the code:
1. `int main ()`: This is the main function where the execution of the program starts.
2. `char *a[2] = {"hello", "hi"};`: This declares an array `a` that can hold 2 pointers to characters. It is initialized with two string literals: "hello" and "hi". Each element of the array `a` points to a string.
3. `printf("%s", *(a+1));`: This line prints the string pointed to by the second element of the array `a`. The expression `*(a+1)` is equivalent to `a[1]`, so it's accessing the second element of the array. Since `a[1]` points to the string "hi", the output will be `hi`.
4. `return 0;`: This line signifies that the program has completed successfully and returns the exit status `0`.
Overall, this code demonstrates how an array of pointers can be used to store and access strings, and how pointer dereferencing can be used to retrieve the values pointed to by the pointers in the array.
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