<<< Pointer Variable | The code snippet has two lines. Let's analyze them step by step:

After analyzing the code, we can conclude that:

Initially, the value of a is uninitialized and can hold any arbitrary value.

The pointer p is set to point two int sizes ahead of a.

The statement *p = 22; assigns the value 22 to the memory location pointed by p. Since p points two int sizes ahead of a, the assignment actually modifies the value at that location, not the value of a itself.

Considering the order of the statements, if you execute the code as it is, without initializing a before these statements, you would encounter undefined behavior. This means the output of printf("%d", a); cannot be predicted reliably.

However, if you were to initialize a before the code snippet, the output of printf("%d", a); would be 100 because the value of a would not be affected by the assignment *p = 22;.

#Programming #Pointers #CodeAnalysis #TechInsights #AbdurRahimRatulAliKhan

>>>