for (i = 1; i <= (number - 1); i++)
{
rem = number % i;
if (rem == 0)
{
sum = sum + i;
}
}
// Input:
// Output:
// 6, 28, 496.....
// 6 = 1 + 2 + 3
//for 6 ... addition of factors without 6 = same 6 is called perfect number
The given code is an implementation of the logic to determine whether a given number is a perfect number or not. A perfect number is a positive integer that is equal to the sum of its proper divisors (excluding the number itself).
Here's a step-by-step description of the logic:
1. The code begins by initializing a variable `sum` to 0. This variable will store the sum of the proper divisors of the given number.
2. It then enters a `for` loop that iterates from 1 to `number - 1`. Each iteration represents a potential divisor of the given number.
3. Inside the loop, the remainder of dividing `number` by the current value of `i` is calculated and stored in the variable `rem`. This is done using the modulo operator `%`.
4. The code checks if `rem` is equal to 0, indicating that `i` is a divisor of `number`. If this condition is true, it means that `i` is a proper divisor of `number`, and it is added to the `sum` variable.
5. After the loop completes, the code outside the loop can determine whether the number is perfect or not. If the `sum` variable is equal to `number`, it means that the sum of the proper divisors (excluding the number itself) is equal to the number, indicating that the number is perfect.
6. Finally, the code may output the result, either displaying the number as a perfect number or not.
To use this code, you would need to provide an input value for `number` and examine the output to determine whether the number is perfect or not.
