<<< Binary Tree

as nodes, n = (2^l)-1

=> log2 (n) = log2((2^l)-1)

  =>  log2 (n + 1) = log2(2^l)

  =>  log2 (n + 1) = l log2(2)

  =>  log2 (n + 1) = l

  =>  l = ceil (log2 (n + 1))

as, n = 7,

now,   l = ceil (log2 (7 + 1)) 

#Programming #Algorithm #CodeAnalysis #BinaryTree #AbdurRahimRatulAliKhan