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Choose Adviser from 3

A chinese emperor had to choose a new adviser amongst 3 sages, all of them equally wise. He placed a problem to them: "To choose one of you, you'll play a simple and fair game: In this sack there are 3 white balls and 2 black balls. Each of you will be blindfolded and will pick one ball and place it on your head. After that, the blindfolds will be removed and each one in turn will try to guess the colour of the ball upon his head, by observation of the other picked balls. However, beware. You may pass your turn in guessing, but if you state a colour and fail, you're disqualified. This way I'll learn which one is the most intelligent amongst you" The sages talked briefly to each other and promptly refused: "Dear lord, it's of no use, since the game is not fair. The last one of us to guess in the first round will know the answer." and the sages promptly demonstrated this to the emperor, who was so amazed by their wits that he appointed all 3 has his advisers. Could you demonstrated it ? NOTE: If the emperor had any wits at all he would have named them all advisers in the first place... maybe spending reduction ? :)
 
Possible View of Advisor 1, to make him pass the turn.
             3    2    1
Case 1:  W    W
Case 2:  W    B
Case 3:  B    W
 
Possible View of Advisor 2, to make him pass the turn.
Case 3: 2 could easily find that he has W, that make 1 to pass the turn. This case is not possible.
Now 2 knows either it is B or W? Still Ambiguous.
            3    2    1
Case 1: W    W
Case 2: W    B
 
Once, 1 and 2 pass, 3 is sure to have W from Case 1 and Case 2 above.
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