Circumference of a Circle
Key Ideas
the circumference is the perimeter of a circle
as you increase the number of sides of a regular polygon, it becomes more and more like a circle
Try the gadget below to see for yourself. Simply enter a value in the box, then press "enter" or click somewhere outside the box
Let's see how we can make use of that.
We'll start with a 4 sided regular polygon (aka square) inscribed in a circle. The only "number" we're given is the radius, R. We want to try to find the perimeter of the square in terms of R.
Since a square has 4 sides, we can make 4 triangles by connecting 4 radii to the 4 corners of the square.
Now, if we could find the length of side AB, we could just multiply it times 4 because there are 4 sides, and then we would have our perimeter. But alas, it won't be so easy. In order to find sides of a triangle, we need right triangles so we can use sine and cosine. So we need to chop triangle AEB into two right triangles.
Now we have a right triangle AEF. If we could figure out ∠AEF. we could use sine to solve for side AF.
Let's figure out ∠AEF. Well, a full rotation around a circle is 360°. But since we divided that into the 4 angles formed by our 4 triangles, each triangle will have the angle (360° ÷ 4). But then we cut that triangle in half, so
∠AEF = (360° ÷ 4) ÷ 2, which is the same thing as
∠AEF = (180° ÷ 4) (we're going to leave it like this to show something later)
So, now we can use sine. Recall
Sine of an Angle =
so
Sin(180° ÷ 4) =
But AF is half of AB, and AB is a side of the square, which we'll call s. This means
AF = (1/2)s
And we can see that
AE = R
Substituting into our sine equation, we get
Sin(180° ÷ 4) =
Multiplying both sides by 2R, we get
2Rsin(180° ÷ 4) = s
or
s = 2Rsin(180° ÷ 4)
Woohoo, we found a side. But since we have 4 sides, we need to multiply times 4 to find the perimeter.
P = 4 x 2Rsin(180° ÷ 4)
Rearranging
P = 2 x 4sin(180° ÷ 4) x R
Now let's try the same thing for a six sided regular polygon (hexagon)
∠AEF = (360° ÷ 6) ÷ 2, which is the same thing as
∠AEF = (180° ÷ 6)
Sin(180° ÷ 6) =
Multiplying both sides by 2R, we get
2Rsin(180° ÷ 6) = s
or
s = 2Rsin(180° ÷ 6)
Woohoo, we found a side. But since we have 6 sides, we need to multiply times 6 to find the perimeter.
P = 6 x 2Rsin(180° ÷ 6)
Rearranging
P = 2 x 6sin(180° ÷ 6) x R
~~~~~~
Now let's see what we have so far. For regular polygons
# of Sides
4
6
Perimeter
P = 2 x 4sin(180° ÷ 4) x R
P = 2 x 6sin(180° ÷ 6) x R
See the pattern? Indeed, we could make the table as long as we want
As you can see, the greater the number of sides, the closer nsin(180° ÷ n) gets to π.
This makes sense, because
We saw that polygons look more and more like a circle the more sides they have.
The more they looks the same, the more their equations should looks the same
Summary
As we increase the number of sides in a regular polygon,
the polygon begins to look more and more like a circle
therefore the perimeter of a polygon becomes closer to the perimeter (circumference) of a circle
the perimeter of a polygon with infinity sides = the circumference of a circle
Now let's think here. Let's compare our formulas for the perimeter of a polygon to the perimeter of a circle
P = 2 x nsin(180° ÷ n) x R
P = 2 x π x R
They actually look kind of similar. Both have a 2, both have an R, and both have something in the middle. Here comes the important part: what happens if I make n (the number of sides) really big?
I checked it in a spreadsheet, and here's what I found.