Tutorial : Balanced Wheatstone Bridge
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Figure 1 : Wheatstone Bridge Circuit
Derive the condition of balance for Wheatstone bridge circuit as shown in Figure 1.
Check Answer Here :
Q/P = R/S this equation is known as the balancing condition in a Wheatstone bridge
Figure 2 : Wheatstone Bridge Circuit
In Wheatstone's bridge P= 9 ohms, Q= 4 ohms and R= 6 ohms. How much resistance must be put in parallel to the resistance S to balance the bridge ?
Check Answer Here :
S = 13.5 Ω
Figure 3 : Wheatstone Bridge Circuit
In a typical Wheatstone network the resistance in cyclic order are A= 10 Ω, B= 5 Ω,C= 4 Ω and D= 4 Ω
How much resistance of resistor needed for add on to the arm B becomes balanced ?
Check Answer Here :
5 Ω resistor should be connected in series with B
Figure 4 : Wheatstone Bridge Circuit
What is the value of unknown resistance R, if galvanometer shows null deflection in the given meter bridge set up shown in the Figure 4?
Given total length of cable is 100 cm.
Check Answer Here :
R = 220 Ω
Figure 5 : Wheatstone Bridge Circuit
Given R1 = 250 Ω
R2 = 500 Ω
R3 = 750 Ω
Find the value of resistor RX, if the Wheatstone Bridge is in balanced condition.
Check Answer Here :
RX = 1500 Ω
Tutorial : Sensitivity of Wheatstone Bridge
Figure a & b : Wheatstone Bridge Circuit
Figure (a) shows a Wheatstone bridge in which P, Q, R, S are fixed resistances, G is a galvanometer and B is a battery. For this particular case the galvanometer shows zero deflection. Now, only the positions of B and G are interchanged, as shown in Figure (b). What is the new deflection of the galvanometer ?
Check Answer Here :
D = 0 (Zero)
Figure 6 : Wheatstone Bridge Circuit
Given P = 1000 Ω
Q = 100 Ω
R = 2005 Ω
S = 200 Ω
Battery Voltage, V = 5V
Current Sensitivity of Galvanometer, S = 10 mm/uA
Internal Resistance of Galvanometer, RG = 100 Ω.
Calculate the deflection of the galvanometer, D in terms of mm.
Check Answer Here :
D = 27.66 mm
Tutorial : Unbalanced Wheatstone Bridge
Figure 7 : Unbalanced Wheatstone Bridge Circuit
Given R1 = 1000 Ω
R2 = 2500 Ω
R3 = 3500 Ω
R4 = 10000 Ω
RG = 300 Ω
V = 6V
Calculate the Thevenin Voltage, VTH , Thevenin Resistance, RTH and Current flow through the Galvanometer, IG for the unbalanced Wheatstone Bridge circuit as shown in Figure 7.
Check Answer Here :
VTH = 0.133 V
RTH = 2777.78 Ω
IG = 43.21 uA
Tutorial : Murray Loop Test
Figure 8 : Murray Loop Test Circuit
Given R1 = 100 Ω
R2 = 300 Ω
Lo = 580 m
Lb = 580 m
The Murray loop test set in the Figure 8 consists of two conductors of the same material and the same cross-sectional area. Both cables are connected 580 m from the test setup at the cable terminal. The bridge is balanced when R1 is 100 Ω and R2 is 300 Ω. Find the distance from the ground fault to the test set.
Check Answer Here :
LX = 290 m
Tutorial : Varley Loop Test
Figure 9 : Varley Loop Test Circuit
Given Total L = 20 km
Rg = 200 Ω
Rs' = 200 Ω
R1 = R2
Varley loop test is performed to locate an earth fault on a 20km long cable. The resistance per km of the single conductor is 20 Ω. The loop is completed with a similar healthy conductor. At balance, the variable resistance connected to the faulty conductor is 200 Ω. The fixed resistance has equal values. Calculate the distance of the fault from the test end.
Check Answer Here :
LX = 5 km
Tutorial : Kelvin Bridge
Figure 10 : Kelvin Bridge Circuit
Given Ra = 1200 Ω
Ra = 1600 Rb
R1 = 800 Rb
R1 = 1.25 R2
Find the value of RX in the Kelvin Bridge circuit as shown in the Figure 10.
Check Answer Here :
RX = 0.3 Ω
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