My numbers that grows over time.
Dimenday = 10(D, 1)10 = 10[D + 1]210 = {10, 10 (D) 2} = {10, 10 [D + 1] 2} where D is the current date (Class 12: Exponentiated polynomial omega level)
Popacthulhum = E100#^^^ ... ^^^#100 (P ^'s) = E100#{P}#100 = E100#{#}#P ≈ 100[1 [2 ¬ 3] 2]2P – 1 = {100, P - 1 [1 [2 ¬ 3] 2] 2} where P is the world population right now (Class 18: Bachmann's collapsing level)
If today is 1st January, 2000, D will equal to 20000101. If today is 31st December, 2022, D will equal to 20221231. And so on.
If the world population is 1,000,000, P will equal to 1,000,000. If the world population is 7,000,000,000,000, P will equal to 7,000,000,000,000. And so on.