Example 5.10: What is the water outlet temperature that could reasonably be obtained, and the heat that could reasonably be recovered from a co-current exchanger, counter-current exchanger, and 1-2 heat exchanger? Use the following information.
Inlet temperature of hot fluid, T1 = 350 °F,
Inlet temperature of cold fluid, t1 = 70 °F,
Specific heat of hot fluid, C = 1 Btu/(lb·°F),
Specific heat of cold fluid, c = 1 Btu/(lb·°F),
Mass flow rate of hot fluid, W = 10000 lb/hr,
Mass flow rate of cold fluid, w = 20000 lb/hr
Solution: For the given situation, R, can be found as
(1) Co-current arrangement: A practical approach at the outlet of the exchanger cannot be less than 5 degrees or Δt = T2 - t2 = 5 °F.
t2:
Outlet temperature of hot fluid, T2 = t2 + Δt = 166.7 °F
Heat transfer rate, Q1:
(2) Counter-current arrangement: In this arrangement practical approach cannot be less than 10 degrees or T2 - t1 = 10 °F.
Outlet temperature of hot fluid, T2 = 70 + 10 = 80 °F.
Outlet temperature of cold fluid, t2:
Heat transfer rate, Q2 (5.31 or 5.32) = 2.7´106 Btu/hr
(3) 1-2 heat exchanger, given R = 2, Use Figure 5.21 to obtain P
P = 0.375 (Fig 5.21)
Outlet temperature of cold fluid, t2:
Outlet temperature of hot fluid, T2:
Heat transfer rate, Q3 = (5.31 or 5.32) = 2.1´106 Btu/hr
The value of Q is the highest for a counter-current arrangement, Q1.