Example 2.16: Estimate the Gibbs energy of formation of water at 350 °K given the following data: ΔHof298 = -57798 cal/mol, ΔGof298 = -54635 cal/mol.
Solution
Entropy of formation ΔSof (Equation 2.48)
Energy of formation, ΔG (Equation 2.48, T = 350 °K)
Heat of formation, ΔHf350 (without Cp data) = ΔH298 = -57798 cal/mol
Entropy of formation, ΔSf350 (without Cp data) = ΔS298 = -10.609 cal/(mol·°K)
Energy of formation, ΔGf350 (Equation 2.48)