E2.14 Vapor Pressure

Example 2.14: Benzene has a vapor pressure of 0.086 bar and 0.9162 bar at 290 °K and 350 °K, respectively. Find the vapor pressure of benzene at 320 °K.

Solution

P₁ = 0.086 bar = 0.086/1.01325 = 0.08488 atm

P₂ = 0.9162 bar = 0.9162/1.01325 = 0.9042 atm

Constant B (Equation 2.45):

Constant A (Equation 2.45):