Example 2.17: How many liters of pure methanol and of pure water must be mixed to form two liters of antifreeze at 25 °C? Partial molar volumes of methanol and water in a 30 mol % methanol solution are:
Methanol (1): V1' = 38.633 cm3/mol, V1 = 40.277 cm3/mol, x1 = 0.3
Water (2): V2' = 17.765 cm3/mol, V2 = 18.068 cm3/mol, x2 = 0.7
Solution VT = 2000 cm3
Specific volume of solution, V = x1V1' + x2V2' = 24.025 cm3/mol
Number of moles of solution, n = VT/V = 83.246 mol
Number of moles of methanol, n1 = x1n = 24.974 mol
Number of moles of water, n2 = x2n = 58.272 mol
Total volume of methanol, V1T = n1V1 = 1017 cm3
Total volume of water, V2T = n2V2 = 1053 cm3