Example 4.12: Calculate the height of the water in an open tank if water is delivered through a pipe having internal diameter of 0.5 in. The smooth brass pipe is 200 ft long. Water is discharged at a rate of 0.01 ft3/s to the atmosphere. The pipeline has an open globe valve (KV = 6.9). Entrance and exit losses are given as Kent = 0.78 and Kexit = 1.0. Use the following information:
Density of water = 62.37 lb/ft3; Viscosity of water = 7.53 ´ 10-4 lb/(ft·s)
Solution:
Cross-sectional area of the pipe, A = 0.00136 ft2.
Velocity of the fluid, V = 7.33 ft/s.
Reynolds number, Re = 2.53 ´ 104.
Friction factor, f = 0.0061.
Skin friction losses:
Fittings and minor loss coefficient, Kf = 6.9 + 1.0 + 0.78 = 8.68
Friction losses hf:
Apply Bernoulli equation (4.20)
Given Z2 = we = 0, P1 = P2, V1 = 0, V2 = 7.33 ft/s, Z1 is found to be 105.8 ft.