Calculation Involving a Limiting Reactant

I. Video on Calculation Involving Limiting Reactants

II. Steps in Finding the Limiting Reactant

STEP 1: Write and balance a chemical equation to get the mole ratios

STEP 2: Underline the compounds in questions and calculate their molar masses

STEP 3: Using the mole ratio from the balanced chemical equation, determine which

reactant will run out first. The reactant that runs out first is the limiting reactant.

STEP 4: Using the limiting reactant, determine the amount of product made using

mass to mass stoichiometry. Refer to the previous lesson.

Exercises

1. For the reaction

2S(s) + 3O₂(g) ---> 2SO₃(g)

if 6.3 g of S is reacted with 10.0 g of O₂, show by calculation which one will be the limiting

reactant.

2. For the reaction

CaCO₃(s) + 2HCl(aq) ----> CaCl₂(aq) + CO₂(g) + H₂O(l)

68.1 g solid CaCO₃ is mixed with 51.6 g HCl. What number of grams of CO₂ will be produced?

3. You react 25.0 g of hydrogen gas with 25.0 g of oxygen gas. Determine the mass of water that

can be produced from these reactants.

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