β‘ Chapter 11: Electricity
π― Class 10 Science Notes (Simple + Exam Focused)
π 1. Electric Current
Current (I) = Flow of electric charge
Formula:
I=QtI = \frac{Q}{t}I=tQβ
Where,
I = Current (Ampere)
Q = Charge (Coulomb)
t = Time (seconds)
π Hindi: Vidyut dhaara charge ke flow hone ko kehte hain.
π 2. Electric Potential and Potential Difference
Electric Potential: Work done to bring a unit charge from infinity to that point.
Potential Difference (V):
V=WQV = \frac{W}{Q}V=QWβ
Where,
W = Work done
Q = Charge
Unit: Volt (V)
π Hindi: Do binduon ke beech ki energy difference ko potential difference kehte hain.
π§² 3. Ohmβs Law
V=IRV = IRV=IR
Where,
V = Potential difference
I = Current
R = Resistance
Graph: V vs I is a straight line.
π Hindi: Ohm ka niyam kehta hai V current ke proportional hota hai.
π§± 4. Resistance
It is the opposition to the flow of current.
Unit: Ohm (Ξ©)
Factors affecting resistance:
Length (R β L)
Area (R β 1/A)
Material
Temperature
π Hindi: Resistance current ke flow mein rukawat hoti hai.
π 5. Resistors in Series and Parallel
πΉ Series Combination:
Total Resistance: R=R1+R2+R3R = R_1 + R_2 + R_3R=R1β+R2β+R3β
Current same, Voltage divides.
πΉ Parallel Combination:
\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} ]
Voltage same, Current divides.
π Hindi: Series mein resistance jodte hain, parallel mein ulte jodte hain.
π₯ 6. Heating Effect of Electric Current
Formula:
H=I2RtH = I^2 R tH=I2Rt
Used in: Electric heater, bulb, geyser etc.
π Hindi: Current se heat generate hoti hai jise hum kaam mein lete hain.
π 7. Electric Power
P=VI=I2R=V2RP = VI = I^2R = \frac{V^2}{R}P=VI=I2R=RV2β
Unit: Watt (W)
1 kW = 1000 W
1 kWh = 1000 watt Γ 1 hour = 3.6 Γ 10βΆ joules
π Hindi: Power ka matlab hai kaam karne ki rate.
π Important Questions β With Answers
β
1 Mark Questions
Define 1 volt.
π 1 volt is the potential difference when 1 joule of work is done to move 1 coulomb of charge.What is the SI unit of electric current?
π Ampere (A)State Ohmβs Law.
π V = IR β Voltage is directly proportional to current if temperature is constant.
β
2 Mark Questions
Write two differences between series and parallel circuits.
Series
Parallel
Current same everywhere
Current divides
Resistance increases
Resistance decreases
Calculate current when 5C charge flows in 10 seconds.
π
I=Qt=510=0.5βAI = \frac{Q}{t} = \frac{5}{10} = 0.5\,AI=tQβ=105β=0.5A
β
3 Mark Questions
Three resistors of 2Ξ©, 3Ξ© and 6Ξ© are connected in parallel. Find total resistance.
π
1R=12+13+16=3+2+16=1βR=1βΞ©\frac{1}{R} = \frac{1}{2} + \frac{1}{3} + \frac{1}{6} = \frac{3+2+1}{6} = 1 \Rightarrow R = 1\,\OmegaR1β=21β+31β+61β=63+2+1β=1βR=1Ξ©
A bulb of 100W works on 220V. Find current and resistance.
π
P=VIβI=PV=100220β0.45βAP = VI \Rightarrow I = \frac{P}{V} = \frac{100}{220} \approx 0.45\,A P=VIβI=VPβ=220100ββ0.45A R=VI=2200.45β489βΞ©R = \frac{V}{I} = \frac{220}{0.45} \approx 489\,\OmegaR=IVβ=0.45220ββ489Ξ©
β
5 Mark Questions
Derive expression for heat produced by electric current.
π
W=VItβH=I2RtW = VIt \Rightarrow H = I^2RtW=VItβH=I2Rt
Use Ohmβs law to derive. Explain applications like heaters and bulbs.
Explain series and parallel combination with formulas and one example each.
π
Explain resistance formulas, where used (series β decorative lights; parallel β homes).