RS Aggarwal Class 10 Solutions Triangles

Hence, AC = 12.5 cm and EC = 8cm

(ii) In ∆ABC, DE || BC, AB = 13.3 cm, AC = 11.9 cm and EC = 5.1 cm

Hence, AD = 7.7 cm

(iii) In ∆ABC, DE || BC, AC = 6.6 cm, [latex s=2]\frac { AD }{ DB } =\frac { 4 }{ 7 } [/latex]

Hence, AE = 2.4 cm

(iv) In ∆ABC, DE || BC, Given [latex s=2]\frac { AD }{ AB } =\frac { 8 }{ 15 } [/latex], EC=3.5cm

RS Aggarwal Class 10 Solutions Triangles

Hence AE = 4 cm

RS Aggarwal Class 10 Solutions Triangles