Material B is cohesive.
I know this because the intercept, which determines the cohesion value, is much higher for material B than that of material A.
The cohesion value of material B is 3948 pascals.
Material A: Shear strength = (0.696*4000)+59= 2843 pascals
Material B: Shear strength = (0.714*4000)+3948 = 6804 pascals
The data defines a linear relationship between shear strength and normal force.
The general formula for a linear expression is y=mx+b.
Material A: y = 0.696x + 59
Material B: y = 0.714x + 3948
Friction angle of material A: S = 0.696x + 59
(S - 59)/x = 0.696
tan^-1 (S-59)/x = undefined
tan^-1 0.696 = 34.84°
Friction angle of material B: S = 0.714x + 3948
(S - 3948)/x = 0.714
tan^-1 (S - 3948)/x = undefined
tan^-1 (0.714) = 35.53°