In this functional group contains fields to enter values for calculation of losses in the Converter/transformer. Neglect the losses or not is up to you.

In the efficiency of the transf. field, enter a value for the transformation efficiency, excluding core losses. The default value is 95%. At your discretion, you can ignore these losses by specifying the value of efficiency in 100%

If you calculate the Converter, then you are available to fill in the field key resistance (Ohm) and the voltage drop on the diode (V).

In the key resistance (Ohm) field, enter the resistance value of the channel of the field-effect transistor or other element used as a key. The default value is 0.06 ohms, depending on the item you are using as a key, this value can be changed.

In the voltage drop on the diode (V) field, the voltage drop on the rectifier diode of the Converter is entered.

Note that the drop value on the diode is the same for all three windings. If the output of one of the windings you do not have a diode or it has a lower voltage drop, then in the functional group Required parameters for this winding, enter the value of the output voltage less by the amount of the drop on the diode (or the difference between the entered drop and the actual drop on the diode installed in this winding).

For example, in the coil 1 you have a diode with 0.7 V drop, and you need to get the output voltage is 10 V, and the winding 2 with a drop of 0.45 Volt and you also need to get the voltage 10V. If you specify in the field the voltage drop across the diode (V) diode coil 1, for the correct calculation of the windings 2, you must enter in the input field of the desired output voltage of this diode (functional group Required parameters) voltage of 0.7 V-0.45 V = 0.25 V less, i.e. 10 V -0,25 V = 9,75 V.

If the winding 2 does not contain a diode at all, then the required voltage on it should be made less by 0.7 V-0 V = 0.7 V, i.e. 10 V-0.7 V = 9.3 V

You will say that for each winding it would be possible to enter its voltage drop on the diode, but this will further load the interface. In General, we must think how much it is in demand, waiting for your feedback and suggestions.