反轉範例
SELECT io_month, [I22], [I23], [M02], [M03]
FROM
(SELECT io_month, pay_id, item_money FROM pay_employee WHERE employee_id = '103183'
AND io_month IN ('201609', '201610')
AND pay_id IN ('I23', 'M03', 'M02', 'I22')) AS pay
pivot
(sum(item_money)
FOR pay_id IN ([I22], [I23], [M02], [M03])
) AS id