Welcome to the ACT math site for Ed-Co HS
We use a system of equations to solve for more than one variable.
EXAMPLE –> { 2x = y - 4 }
{ 3x + y = 9}
There are multiple ways to solve the system.
One way is by using substitution.
STEP 1: one of the equations has to be set equal to x or y
We will use the top equation 2x = y - 4 and set the it equal to y 2x = y - 4
To get y alone we have to add 4 to both sides (2x) + 4 = (y - 4) + 4
We are left with the system as {2x + 4 = y}
{3x + y = 9}
STEP 2: We now have to substitute the equation we set equal to y into
the second equation to make one equation with one variable
3x + (2x + 4) = 9
5x + 4 = 9
Now we have to solve for x (5x + 4) - 4 = (9) - 4
5x = 5
5 5
x = 1
STEP 3: We then take x and plug it back into one of the equations to find y
y = 2(1) + 4
y = 8
The second way is elimination
STEP 1: We have to make the two equations look similar {2x = y - 4} -> {2x - y = -4}
{3x + y = 9} {3x +y = 9 }
Now we can add the two systems together 5x + (0y) = 5
5x = 5
5 5
x = 1
STEP 2: plug x back into one of the equations.
2 • (1) = y - 4
(2) + 4 = (y - 4) +4
6 = y
The third way to solve a system is by using a graphing utility.
STEP 1: graph one of the equations –> 2x = y - 4
STEP 2: graph the second equation –> 3x + y = 9
STEP 3: Find where the two lines intersect on the same plane
The lines cross at (1,6). x = 1 and y = 6