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Calculation example from KUDU
Calculation example from KUDU
KUDU
According to §3.10.3 of EN 1993-1-8
Equal leg angles in tension
Profile: Bolts: Forces:
type =70x70x7 Amount =2 FEd = 56 kN
Quality =S 355 d =16 mm γ M2 = 1,25
Quality =8.8 γM0 = 1,00
e1 = 40 mm
e2 = 35 mm
p1 = 80 mm
A single angle in tension connected by a single row of bolts in one leg, see Figure 3.9, may be treated as concentrically loaded over an effective net section for which the design ultimate resistance should be determined as follows:
1. Section Check
With 1 bolt:
With 2 bolts:
With 3 or more bolts:
β = 0,63
Anet = 814mm²
Nu,Rd = 194kN
NEd / Nu,Rd = 0,29 < 1,00
2. Shear resistance
Fv,Rd = 60,288kN
ΣFv,Rd = 120,576kN
FEd / Fv,Rd = 0,46 < 1,00
β2 and β3 are reduction factors dependent on the pitch p1 as given in Table 3.8. For intermediate values of p1 the value of β may be determined by linear interpolation;
Anet is the net area of the angle. For an unequal-leg angle connected by its smaller leg, Anet should be taken as equal to the net section area of an equivalent equal-leg angle of leg size equal to that of the smaller leg.
3. Bearing resistance
Fb1,Rd = 77,99kN
k1 = 2,5
αb = 0,74
Fb2,Rd = 77,99kN
k1 = 2,5
αb = 0,74
Fb,Rd = 77,99kN
FEd / Fb,Rd = 0,36 < 1,00
4. Block tearing
Veff1,Rd = 112,91kN
Ant = 182mm²
Anv = 217mm²
FEd / Veff1,Rd = 0,25 < 1,00
ΣVeff1,Rd = 170,30kN
Ant = 182mm²
Anv = 497mm²
NEd / ΣVeff1,Rd = 0,33 < 1,00
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