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> > > > Five nanoseconds is how long it takes for "a fallen shell's volume" to equal the volume of all the protons and neutrons in a planet.
> > > > When things fall on earth, they have an acceleration that is the same all over the planet, at a radius R from the center.
> > > > Potentially, many objects can fall at this 9.8 meters per second, anywhere around the Earth.
> > > > The area where this acceleration is correct is A :
> > > >
> > > > A = 4 pi R^2
> > > >
> > > > z = 1/2 at^2
> > > >
> > > > The height fallen is z. The volume of a fallen shell is V1, when z is much less than R.
> > > >
> > > > V1 = zA
> > > >
> > > > That volume is equal to V2 after a 5ns fall. After a fall of time t,
> > > >
> > > > V1 / t = V2 / 5ns
> > > >
> > > > That is the conservation of the momentum of free space, where V2 = NV.
> > > > The volume of a proton is V, using the proton radius of 0.95fm.
> > > > N is the number of baryons in a planet.
> > > >
> > > > 5ns is the universal constant for the conservation of continuum
> > > >
> > > > 5ns is how long it takes the volume of a fallen shell to equal the volume of the baryons in the planet or star.
> > > > This is gravity volume theory.
> > >
> > > 5.23961254 nanoseconds * c = 1.57079632 meters
> > >
> > > Hello Mr Folmsbee have you ever tried 5.23961254 nanoseconds?
> > >
> > >
> > > ((pi/2e+12)^0.5 / 6.67406745595e-11)^0.5 = 137.036
> > >
> > > (((137036^4) * (6.67406745595e-11^2)) * 2) = pi
> > >
> > > 1 / ((30299792458^2) / (1.23558996e+20 * (2 * pi))) = 0.84561938763
> > >
> > > https://sites.google.com/site/lordkronosprime/theory-of-everything
> >
> > Hello DF, Yes, I tried that range of number 5.24ns. It depends on the proton radius used.
> > When I use 0.95fm for r, tau is 5.1315ns.
> > But a different r gives diff tau. The ratio is invariant : V / tau
> >
> > where V = 4/3 pi r^3
> >
> > V/ tau = zA / (N second)
> >
> > tau = NV second / zA
> >
> > N is number of baryons in planet, N=M/m
> > z is height fallen in 1 second, A is area of planet
> >
> >
> > 5.13ns =
>
> (pi / 2) / the speed of light = 5.23961255e-9
>
> (((pi / 1.02106165) / 2) / c) / 5.131534e-9 = 0.999999997 s / m
>
>
> pi / 1.02106165 = 3.07679037166
>
> Yah ... Pi goes PolyHedral
>
>
> where V = 4/3 * 3.07679037166 * r^3
>
> http://i57.tinypic.com/294ksba.jpg
>
> Time Draws "IN"
> While
> Space travels "OUT"
(((433494437^2) / (300000000^2)) / 2)^0.5 = 1.0217561867 ....
There it is AGAIN (N+1)^2/2 or (N+1)^0.5*2 ... Kinetic Energy of Planck Momentum
a Planck unit theory: sqrt of Planck momentum as a link between mass and charge
Malcolm J. Macleod
http://vixra.org/pdf/1102.0032v8.pdf
1.02106165 / ((((433494437^2) / (300000000^2)) / 2)^0.5) = 0.99932025202
1.02106165/(433494437^2 / 300000000^2 /2)^0.5*3e+8 = 299796075.608
> 1 / ((c / 0.02) * (((0.7062513306^2) * 2)^(1 / 5.77355))) = 6.67407998e-11
>
> 3 + (1 / 7.062513306) = 3.14159265359
>
> 1 / (0.577355^2) = 2.99995083658
>
> G * ((c / 0.02) * (((0.7062513306^2) * 2)^0.3)) = 0.99969307
Euler's constant / 0.577355 = 0.9997586665
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