Stoichiometry is the division of chemistry that looks at the relationships between the amounts of reactants and/or products. In Greek, stoikhein means element and metron means measure, so stoichiometry literally translated means the measure of elements.
Stoichiometry is all about determining the correct proportions to combine reactants in. This might sound scary (stoichiometry is certainly a mouthful!) but if you have ever cooked or baked you have already done stoichiometry.
We can think of a chemical equation like a cooking recipe. It tells us how much of each ingredient (reactant) we need and how much product (serving size) we expect to make.
A basic chocolate chip cookie recipe for 1 doze cookies is as follows:
2 ¼ cups flour
2 large eggs
1 teaspoon baking soda
1 stick of butter
¾ cup packed light brown sugar
2 large eggs
One bag of chocolate chips
If you answered 4 ½ cups flour then you are a chemical stoichiometer!
2 ⅛ cups flour
Let's apply what we learned above to a chemical equation.
3 CH4 and 6 O2
because we can triple the recipe to make 6 water
3CH4 + 6O2 → 3CO2 + 6H2O
No, because that would require 2.5 CH4 and we can't split molecules in half. We can only have whole numbers in the coefficients.
Chemists do not usually conduct reactions with single molecules because they are too small to work with in the lab.
Instead, chemists work with moles of a chemical because it is a large enough amount that it can be converted into grams and weighed in the lab. We can interpret the coefficients in a chemical equation to stand for moles.
We can interprets this reaction to read "one mole of methane molecules and two moles of oxygen molecules react to form one mole of carbon dioxide and two moles of water molecules."
To find out how much "one mole methane molecules" weighs in the lab (or any chemical for that matter) we multiply the number of moles by the molar mass.
1 mol x (12.01 + 4(1.01)) g/mol = 16.05 g
So in the lab one mole of methane will weigh 16.05g.
Different from single molecules we can have half a mole.
So we can make 5 moles of water using the above reaction:
it requires 2.5 moles CH4 and 5 moles O2
because we can multiply the recipe by 2.5
2.5CH4 + 3O2 → 2.5CO2 + 5H2O