Functioning of switch case statement

First, the integer expression specified in the switch statement is evaluated. This value is then matched one by one with the constant values given in the different cases. If a match is found, then all the statements specified in that case are executed along with the all the cases present after that case including the default statement. No two cases can have similar values. If the matched case contains a break statement, then all the cases present after that will be skipped, and the control comes out of the switch. Otherwise, all the cases following the matched case will be executed.

Let's see a simple example of c language switch statement.

1. #include<stdio.h>  

2. int main(){    

3. int number=0;     

4. printf("enter a number:");    

5. scanf("%d",&number);    

6. switch(number){    

7. case 10:    

8. printf("number is equals to 10");    

9. break;    

10. case 50:    

11. printf("number is equal to 50");    

12. break;    

13. case 100:    

14. printf("number is equal to 100");    

15. break;    

16. default:    

17. printf("number is not equal to 10, 50 or 100");    

18. }    

19. return 0;  

20. }    

Output

enter a number:4

number is not equal to 10, 50 or 100

enter a number:50

number is equal to 50

Switch case example 2

1. #include <stdio.h>  

2. int main()  

3. {  

4.     int x = 10, y = 5;   

5.     switch(x>y && x+y>0)  

6.     {  

7.         case 1:   

8.         printf("hi");  

9.         break;   

10.         case 0:   

11.         printf("bye");  

12.         break;  

13.         default:   

14.         printf(" Hello bye ");  

15.     }   

16.           

17. }  

Output

hi

C Switch statement is fall-through

In C language, the switch statement is fall through; it means if you don't use a break statement in the switch case, all the cases after the matching case will be executed.

Let's try to understand the fall through state of switch statement by the example given below.

1. #include<stdio.h>  

2. int main(){    

3. int number=0;    

4.   

5. printf("enter a number:");  

6. scanf("%d",&number);  

7.   

8. switch(number){  

9. case 10:  

10. printf("number is equal to 10\n");  

11. case 50:  

12. printf("number is equal to 50\n");  

13. case 100:  

14. printf("number is equal to 100\n");  

15. default:  

16. printf("number is not equal to 10, 50 or 100");  

17. }  

18. return 0;  

19. }    

Output

enter a number:10

number is equal to 10

number is equal to 50

number is equal to 100

number is not equal to 10, 50 or 100

Output

enter a number:50

number is equal to 50

number is equal to 100

number is not equal to 10, 50 or 100

Nested switch case statement

We can use as many switch statement as we want inside a switch statement. Such type of statements is called nested switch case statements. Consider the following example.

1. #include <stdio.h>  

2. int main () {  

3.   

4.    int i = 10;  

5.    int j = 20;  

6.    

7.    switch(i) {  

8.      

9.       case 10:   

10.          printf("the value of i evaluated in outer switch: %d\n",i);  

11.       case 20:  

12.          switch(j) {  

13.             case 20:  

14.                printf("The value of j evaluated in nested switch: %d\n",j);  

15.          }  

16.    }  

17.      

18.    printf("Exact value of i is : %d\n", i );  

19.    printf("Exact value of j is : %d\n", j );  

20.    

21.    return 0;  

22. }  

Output

the value of i evaluated in outer switch: 10

The value of j evaluated in nested switch: 20

Exact value of i is : 10

Exact value of j is : 20