Exam 1 Review and Q and A,

Questions 3-4 EXAM 1

Hello everyone,

I wanted to share questions 3 and 4 from Exam 1. To be transparent, I didn't perform as well as I had hoped on these, but I'm optimistic about improving in the future. Now that I'm collaborating with a team, I feel more hopeful. Together, we're aiming to excel in the upcoming second exam. Without further ado, here are questions 3 and 4 from my first exam.

3A

For the first scenario, it becomes quite straightforward once you remember that if there's a reflection across the y-axis, the function is even. If there's no such reflection, the function is odd. However, it's important to note that if there's no reflection through the y-axis and the function doesn't pass through the origin, then it is considered undefined.

3B

In this instance, my most significant error was mistakenly reflecting the figure over the x-axis, which was not the requirement of the question. Instead, the correct approach was to reflect over the line y=x, owing to the equation being a cubic function and it satisfying the horizontal line test.

4

A) We need to use the formula m=y2-y1 / x2-x1 which is in this case 2-4/-3-1 which gives us -2/-4 and this is a slope of 0.5.


B) Now that we got the slope we plug it in to get the y intercept and plug one of the y coordinates given in my case I used 4 now we plug it into y=mx+b and we get 4=0.5(1)+B subtract the 0.5 on both sides and we get a y intercept of 3.5 so Y=3.5. Now with the slope and Y intercept we can now solve for the X intercept by plugging in and equaling it to 0 so 0=0.5x+3.5 and we subtract 3.5 on both sides and now we have -3.5=0.5x which the final step is to divide -3.5 by 0.5 and we get an X intercept of -7 so X=-7

C)For this one the sketch can be found on the drawing on top but the points of interception are (0,3.5) and (-7,0).