Give you an integer array (index from 0 to n-1, where n is the size of this array)，find the longest increasing continuous subsequence in this array. (The definition of the longest increasing continuous subsequence here can be from right to left or from left to right)
Have you met this question in a real interview?
Yes
Example
For [5, 4, 2, 1, 3], the LICS is [5, 4, 2, 1], return 4.
For [5, 1, 2, 3, 4], the LICS is [1, 2, 3, 4], return 4.
Note
O(n) time and O(1) extra space.
public class Solution { /** * @param A an array of Integer * @return an integer */ public int longestIncreasingContinuousSubsequence(int[] A) { // Write your code here int res = 0 ; if(A == null || A.length == 0){ return res; } boolean left = true; int start = 0 ; res = 1; for(int i = 1 ; i < A.length ; i++){ if(A[i] > A[i-1]){ if(left){ res = Math.max(res, i - start + 1); } else{ start = i - 1; left = true; } } else if( A[i] < A[i-1]){ if(!left){ res = Math.max(res, i - start + 1); } else{ start = i - 1; left = false; } } } return res; } }