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The Oracle Of Delphi, Major Thirds & The Delian Problem -->
The Oracle Of Delphi, Major Thirds & The Delian Problem -->
The Pythia, commonly known as The Oracle of Delphi, was the name of any priestess throughout the history of The Temple of Apollo at Delphi, which was located on the slopes of Mount Parnassus, beneath the Castalian Spring on the north shore of the Corinthian Gulf in Greece.
The Pythia, commonly known as The Oracle of Delphi, was the name of any priestess throughout the history of The Temple of Apollo at Delphi, which was located on the slopes of Mount Parnassus, beneath the Castalian Spring on the north shore of the Corinthian Gulf in Greece.
The Pythia, dating as far back as 1400 BC, was widely credited for her prophecies inspired by being filled by the spirit of god, in this case Apollo.
The Pythia, dating as far back as 1400 BC, was widely credited for her prophecies inspired by being filled by the spirit of god, in this case Apollo.
..."The Delian Problem owes its name to a story retold by Plutarch concerning the citizens of Delos, who consulted The Oracle At Delphi in order to learn how to defeat a plague sent by Apollo. The oracle responded that they must double the size of the altar to Apollo, which was a regular cube.
..."The Delian Problem owes its name to a story retold by Plutarch concerning the citizens of Delos, who consulted The Oracle At Delphi in order to learn how to defeat a plague sent by Apollo. The oracle responded that they must double the size of the altar to Apollo, which was a regular cube.
The Major Third, The Minor Sixth & The Delian Problem -->
The Major Third, The Minor Sixth & The Delian Problem -->
Notice how, sequentially/ascending, from low to high, from small to large,
Notice how, sequentially/ascending, from low to high, from small to large,
reciprocals MAJOR THIRD & MINOR SIXTH
reciprocals MAJOR THIRD & MINOR SIXTH
show expansion towards the Octave (Volumetric 8 times as large)
show expansion towards the Octave (Volumetric 8 times as large)
by the proportions of the cube root of 2 & the cube root of 4
by the proportions of the cube root of 2 & the cube root of 4
showing expansion towards the Octave (Frequency 2 times as large)
showing expansion towards the Octave (Frequency 2 times as large)
There is a simple neusis construction using a marked ruler for a length which is the 3√2 times another length.
Mark a ruler with the given length, this will eventually be GH.
Construct an equilateral triangle ABC with the given length as side.
Extend AB an equal amount again to D.
Extend the line BC forming the line CE.
Extend the line DC forming the line CF
Place the marked ruler so it goes through A and one end G of the marked length falls on CF and the other end of the marked length falls on ray CE. Thus GH is the given length.
The AG is the given length times 3√2.
Notice how the symbol used for the MINOR THIRD, an equilateral triangle, can be used to construct the very formula that is it's own proportion {1.259} !! 💥🤯
Notice how the symbol used for the MINOR THIRD, an equilateral triangle, can be used to construct the very formula that is it's own proportion {1.259} !! 💥🤯
Solve Cube Roots of Simple Numbers by Hand -->
Solve Cube Roots of Simple Numbers by Hand -->
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