The rules for simplifying algebraic expressions (expanding parentheses, collecting like terms)
Simplify algebraic expressions
Warm-up - Accessing prior knowledge
1. Which of these representations does not tell us to multiply?
a. 3(4) c. 6 . 7
b. 2m d. 8 x 10
2. Use mental math to compute (learners explain reasoning when sharing answers).
a. 3 + (17 + 38) d. 2(13) + 2(7)
b. 1 + (1/2 + 4 + 1/2) e. 5(3 + 10)
c. 5 x 26 x 2 f. 231 . 8 . 0
3. Compute using the correct order of operations (learners explain reasoning when sharing answers).
3 + 5^2 (9 - 3 (-1 + 4))
The main part of the lesson, will start with the learners watching a video on simplifying expressions (see attached).
While the video is playing, the teacher will stop it at various points and ask learners questions on what was said, to gauge their understanding and keep them active in the lesson.
A term is an individual part of an expression and typically appears in one of three forms:
A number by itself
A letter by itself
A combination of letters and numbers
Like terms have the same combination of letters. To add or subtract terms with the same letter, we add or subtract the numbers like usual and just put the letter back on the end.
Linear expressions are those in which all variables (i.e. the letters) are to the power of 1 so there are no squared or cubed terms.
Example: simplify the following, 2a+3+a+5
We have to group the terms that are similar; all the terms that are just numbers need grouping together and simplifying, as do the similar algebraic terms.
This gives,
2a + 1a=3a
3 + 5=8
Sometimes terms have more than one variable (letter) multiplied or divided together:
xy + y + 2xy
in this instance,
xy and
2xy, are like terms that can be added together to simplify the expression, hence we find,
3xy + y
Terms of certain powers have to be grouped with terms of the same power. Such terms can also include multiple letters and powers.
2x²y + xy² + 3x²y + 5xy²
= 5x²y+6xy²
2x²y and 3x²y are like terms xy² and 5xy² are like terms.
Simplify the expression 3y + 2x + 4x − y.
3y and −y are like terms
2x and 4x are like terms
Example 1: (Teacher led example)
Whenever a problem can be simplified, you should simplify it before substituting numbers for the letters. This will make your job a lot easier! To simplify an algebraic expression: (2 . 3) + 2(x) + x(1) -x(4x) + 5
Clear the parentheses. 2 . 3 + 2 . x + x . 1 - x . 4x + 5
= 6 + 2x + x - 4x² + 5
Combine like terms by adding coefficients. 6 + 2x + x - 4x² + 5
= 6 + 3x - 4x² + 5
Combine the constants.
6 + 3x - 4x² +5
= 11 + 3x - 4x²
Example 2: (Teacher led example with student discussion)
Before you evaluate an algebraic expression, you need to simplify it. This will make all your calculations much easier. Here are the basic steps to follow to simplify an algebraic expression:
remove parentheses by multiplying factors
use exponent rules to remove parentheses in terms with exponents
combine like terms by adding coefficients
combine the constants
Let's work through an example.
When simplifying an expression, the first thing to look for is whether you can clear any parentheses. Often, you can use the distributive property to clear parentheses, by multiplying the factors times the terms inside the parentheses. In this expression, we can use the distributive property to get rid of the first two sets of parentheses.
Now we can get rid of the parentheses in the term with the exponents by using the exponent rules we learned earlier. When a term with an exponent is raised to a power, we multiply the exponents, so (x2)2 becomes x4.
The next step in simplifying is to look for like terms and combine them. The terms 5x and 15x are like terms, because they have the same variable raised to the same power -- namely, the first power, since the exponent is understood to be 1. We can combine these two terms to get 20x.
Finally, we look for any constants that we can combine. Here, we have the constants 10 and 12. We can combine them to get 22.
Now our expression is simplified. Just one more thing -- usually we write an algebraic expression in a certain order. We start with the terms that have the largest exponents and work our way down to the constants. Using the commutative property of addition, we can rearrange the terms and put this expression in correct order, like this.
F - First - Multiply the first terms in each set of parentheses
O - Outer - Multiply the outer terms in each set of parentheses
I - Inner - Multiply the inner terms in each set of parentheses
L - Last - Multiply the last terms in each set of parentheses
(3 + 7x)(6 + 2x)
1. Multiply first terms
(3 + 7x)(6 + 2x)
= 18
2. Multiply outer terms
(3 + 7x)(6 + 2x)
= 18 + 6x
3. Multiply inner terms
(3 + 7x)(6 + 2x)
= 18 + 6x + 42x
4. Multiply last terms
(3 + 7x)(6 + 2x)
= 18 + 6x + 42x + 14x^2
5. Combine like terms by adding/subtracting
= 18 + 6x + 42x + 14x^2
= 18 + 48x + 14x ²
Learner will complete three questions on the white boards that have been provided with. After a couple of minutes to complete the question, the teacher will say 'times up' and learners will need to hold up their boards with their answers.
1. 4x(x-2) - 3x(x-1)
2. (2a - 3)(4a - 1)
3. 3x(2x + y) - (3x + y)(x - 2y)
Learners sharing and explaining their answers with the rest of the class.
http://webbapp.liber.se/matematikboken-z/#
http://webbapp.liber.se/matematikboken-z/#/2-algebra
Textbook Work:
ETT pg. 71 no. 2034 abc, 2035
TVÅ pg. 72 no. 2042, 2043 abc, 2045 abc, 2046, 2047 ab
TRE pg. 73 no. 2049 ab, 2051 ab, 2052 abc, 2053 ab, 2055 ab
FYRA pg. 74 no. 2058 ab, 2059 ab, 2060, 2061, 2062 ab, 2063