Cl
number of outer electrons 7
number of energy levels 3
group number 17
period 3
number of total electrons17
number of electrons in 3rd energy level 7
number of electrons in 2nd energy level 8
block p
C
number of outer electrons 4
number of energy levels 2
group number 14
period 2
number of total electrons 6
number of electrons in 3rd energy level 0
number of electrons in 2nd energy level 4
block p
Au
number of outer electrons 2
number of energy levels 6
group number 11
period 6
number of total electrons 79
number of electrons in 1st energy level 2
number of electrons in 2nd energy level 8
block d
Ca
number of outer electrons 2
number of energy levels 4
group number 2
period 4
number of total electrons 20
number of electrons in 1st energy level 2
number of electrons in 2nd energy level 8
block s
Identify the element
a. 1s2 2s2 2p6 3s2 3p1 Al
b. 1s 11 2s11 2p 11 11 1 F
c. [Ar] 4s2 3d1 Sc
d. 1s2 2s2 2p6 3s2 3p6 Ar
e. 1s 11 2s11 2p 11 11 11 3s11 3p1 1 1 P
f. [Ar] 4s2 3d10 4p2 Ge
g. 1s2 2s2 2p6 3s2 Mg
h. 1s 11 2s11 2p 1 B
i. [Ar] 4s2 3d8 Ni
j. 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4 Se
k. 1s 11 2s11 2p 11 11 11 3s11 Mg
l. [Ar] 4s2 3d10 Zn
mole problem weigh an old penny and new penny. The old penny is made of __Cu_______ the new penny is mostly ___Zn_____. With this information, calculate the moles of each, the atoms of each present, and finally the number of atoms you could give everyone in the US ( Population 300 million) if you shared.
old penny : 3.1 g /64g = .048mole; .048mole * 6.02*1023 = .29* 1023 = 2.9 *1022 atoms; 2.9*1022atoms/3*108 people = .97 *1014 = 9.7 *1013 atoms per person
new penny : 2.5 g /65g = .038mole; .038mole * 6.02*1023 = .23* 1023 = 2.3 *1022 atoms; 2.3*1022atoms/3*108 people = .77 *1014 = 7.7 *1013 atoms per person