ch4e practice answers

Cl

number of outer electrons 7

number of energy levels 3

group number 17

period 3

number of total electrons17

number of electrons in 3rd energy level 7

number of electrons in 2nd energy level 8

block p

C

number of outer electrons 4

number of energy levels 2

group number 14

period 2

number of total electrons 6

number of electrons in 3rd energy level 0

number of electrons in 2nd energy level 4

block p

Au

number of outer electrons 2

number of energy levels 6

group number 11

period 6

number of total electrons 79

number of electrons in 1st energy level 2

number of electrons in 2nd energy level 8

block d

Ca

number of outer electrons 2

number of energy levels 4

group number 2

period 4

number of total electrons 20

number of electrons in 1st energy level 2

number of electrons in 2nd energy level 8

block s

Identify the element

a. 1s² 2s² 2p⁶ 3s² 3p^{1 Al}

b. 1s 11 2s11 2p 11 11 1 F

c. [Ar] 4s² 3d^{1 Sc}

d. 1s² 2s² 2p⁶ 3s² 3p^{6 Ar}

e. 1s 11 2s11 2p 11 11 11 3s11 3p1 1 1 P

f. [Ar] 4s² 3d¹⁰ 4p^{2 Ge}

g. 1s² 2s² 2p⁶ 3s² Mg

h. 1s 11 2s11 2p 1 B

i. [Ar] 4s² 3d^{8 Ni}

j. 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p^{4 Se}

k. 1s 11 2s11 2p 11 11 11 3s11 Mg

l. [Ar] 4s² 3d^{10 Zn}

mole problem weigh an old penny and new penny. The old penny is made of __Cu_______ the new penny is mostly ___Zn_____. With this information, calculate the moles of each, the atoms of each present, and finally the number of atoms you could give everyone in the US ( Population 300 million) if you shared.

old penny : 3.1 g /64g = .048mole; .048mole * 6.02*10²³ = .29* 10²³ = 2.9 *10²² atoms; 2.9*10²²atoms/3*10⁸ people = .97 *10¹⁴ = 9.7 *10¹³ atoms per person

new penny : 2.5 g /65g = .038mole; .038mole * 6.02*10²³ = .23* 10²³ = 2.3 *10²² atoms; 2.3*10²²atoms/3*10⁸ people = .77 *10¹⁴ = 7.7 *10¹³ atoms per person