Consider parallelogram ABCD whose diagonals AC, BD intersect at E.
∠DAC = ∠ACB ...(Alt. ang.s on parallels DA BC)
∠ADB = ∠CBD ...(Alt. ang.s on parallels DA BC)
AD = BC ...(Opp. sides of parallelogram are equal)
∴ ∇ADE ≡ ∇CEB ...Two angles and incl. side equal)
∴ DE = EB and AE = EC