Consider 2 straight lines AB, CD intersecting at O
AO can be rotated about O so that it lies upon CO, occupying the same set of points
The amount of revolution is known as the angle AOC
If AO continues to rotate about O until it once again overlays its original position it will have performed 1 revolution.
One measure divides 1 revolution into 360 degrees, each degree into 60 minutes and each minute into 6o seconds i.e.
1 revolution = 360 degrees = 2,160 minutes = 1,296,000 seconds
(5º is shorthand way of writing 5 degrees)
CD is a straight line.
O is a position that lies on CD and AO is another straight line.
∠AOD is the amount a line OD needs to be rotated to position it over OA.
(“∠” is the symbol for angle)
All values for this angle are possible, including the one that satisfies
∠AOD = ∠AOC
This angle is called a right angle (rt. ang.) and AD is said to be perpendicular to CD
If one rotates AO another 1 rt. ang. anti-clockwise it lies on CO
since ∠AOD = ∠AOC = 1 rt. ang
This is equivalent to rotating OD through 2 rt. ang.s.
But CO is part of straight line CD, so a straight line may be thought of the addition of 2 rt. ang.s.
BO is drawn such that ∠COB = ∠BOD then as before these are rt. ang.s
then as AB is also built of 2 rt. angs. it is also a straight line.
So 4 rt. ang.s = 1 revolution = 360º ∴ 1 rt. ang. = 90º
(Currently we have shown how a rt. ang. can exist, later it will be shown how to construct one)
AB & CD are two straight lines intersecting at O.
Let MN be a line passing through O perpendicular to AB
∴ ∠MOB = ∠NOB = ∠AON = ∠AOM = 1 rt. ang.
∠DOB = 1 rt. ang. - ∠NOD
∠AOC = 2 rt. ang.s - ∠AOD
= 2 rt. ang.s - 1 rt. ang. - ∠NOD
= 1 rt. ang. - ∠NOD
= ∠DOB
Similalry ∠DOA = ∠COB AB & CD are two straight lines intersecting at O.
Let MN be a line passing through O perpendicular to AB
∴ ∠MOB = ∠NOB = ∠AON = ∠AOM = 1 rt. ang.
∠DOB = 1 rt. ang. - ∠NOD
∠AOC = 2 rt. ang.s - ∠AOD
= 2 rt. ang.s - 1 rt. ang. - ∠NOD
= 1 rt. ang. - ∠NOD
= ∠DOB
Similalry ∠DOA = ∠COB