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Addition, Subtraction, Division & Multiplication Questions - Give Them Ago - Answers Next Week When We Upload The Next Set
Story Maths Questions - Problem Solving Maths Questions in a story - These questions are suitable for Age 10 Children
Title: "Ashington's Adventure in Northumberland"
Mathematical Skills Covered: Addition, Multiplication, Area Calculation
Long ago in Northumberland, lived a bright and adventurous boy named Ashington. He was 10 years old and loved to explore his beautiful surroundings. One day, Ashington decided to embark on a grand adventure to the Northumberland National Park, hoping to solve some mathematical mysteries that were rumoured to be hidden there.
As Ashington set off on his adventure, he found a narrow path marked with numbers. The first marker showed the numbers '3' and '7'. Remembering his addition skills, Ashington worked out that these numbers added up to '10'.
Question: What is 3 + 7?
Walking further, he found another marker depicting '6' and '4'.
Question: What is 6 + 4?
Ashington continued his journey, finding and solving these addition mysteries until he had solved five in total.
Question: Solve the following addition problems: 8 + 2, 7 + 3, 5 + 5.
Suddenly, the path changed and the markers started showing multiplication puzzles. The first one was '2' and '5'. Ashington, applying his multiplication knowledge, found the answer.
Question: What is 2 x 5?
Then, he came across another marker showing '3' and '4'.
Question: What is 3 x 4?
Ashington continued to solve these new multiplication problems and managed to solve a total of five, just like the addition problems.
Question: Solve the following multiplication problems: 3 x 3, 2 x 5, 4 x 2.
Finally, Ashington arrived at a large, square field, rumoured to hide a treasure. The field was marked with two numbers '20' and '20'. Ashington recalled that these numbers could be used to calculate the area of the square field.
Question: What is the area of a square with sides of 20 metres each?
Emboldened by his findings, Ashington found another field, this time a rectangle, with sides marked '15' and '25'.
Question: What is the area of a rectangle with a length of 25 metres and a width of 15 metres?
After solving these area problems, Ashington was able to unlock the secret treasure: a chest full of knowledge and the ability to see the beauty of mathematics in the world around him.
Question: Calculate the total area of both fields.
Question: If another rectangular field had an area of 200 square metres and one side was 10 metres, what would be the length of the other side?
Full Answers and explanations to solving the questions:
Addition of 3 and 7 results in 10. This is because when we add three units to seven units, we get a total of ten units.
When we add 6 and 4, it equals 10. This is because adding six units to four units equals ten units in total.
For the addition problems:
8 + 2 equals 10 because adding two units to eight units gives us ten units.
7 + 3 equals 10 because adding three units to seven units totals ten units.
5 + 5 equals 10 because adding five units to another five gives us ten units.
Multiplication of 2 and 5 gives 10. This is done by adding 2 to itself five times, which results in 10.
Multiplying 3 by 4 equals 12. This is achieved by adding 3 to itself four times, which sums up to 12.
For the multiplication problems:
3 x 3 equals 9. This is because adding 3 to itself three times gives us a total of 9.
2 x 5 equals 10. This is done by adding 2 to itself five times, which equals 10.
4 x 2 equals 8. We get this by adding 4 to itself twice, summing up to 8.
The area of the square is calculated by multiplying the length of one side by itself. Here, each side of the square is 20 m, so the area is 20 m x 20 m = 400 square metres.
The area of the rectangle is calculated by multiplying the length of the rectangle by its width. Here, the length is 25 m and the width is 15 m, so the area is 25 m x 15 m = 375 square metres.
The total area of both fields is calculated by adding the area of the square and the area of the rectangle. So, the total area is 400 sq m (square field) + 375 sq m (rectangular field) = 775 sq m.
To find the length of the other side of the rectangular field, we divide the total area by the known side. Here, the area is 200 sq m and one side is 10 m, so the length of the other side is 200 sq m / 10 m = 20 m.