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Quick Math Question 1:
A car can travel a distance of 15 km distance with 800 millilitres of petrol. How much distance the car will cover 4 litres of petrol?
90 km
100 km
75 km
80 km
Answer (Detailed Solution Below)
Option 3 : 75 km
Quick Math Question 1 Detailed Solution
Concept used:
1 litre = 1000 millilitre
Calculation:
The distance covered by the car in 800 ml of petrol = 15 km
The distance covered by the car in 1 ml of petrol = 15/800 km
The distance covered by the car in 4000 ml of petrol = (15/800) × 4000 km = 75 km
∴ The distance covered by the car in 4 litre of petrol is 75 km
Quick Math Question 2:
Which of the following will have 1 at its units place?
192
172
182
162
Answer (Detailed Solution Below)
Option 1 : 192
Quick Math Question 2 Detailed Solution
Concept:
91 = 9, 92 = 81 (unit digit is 1), 93 = 729 (unit digit is 9) and so on...
Solution:
192 = 361.
Hence, the correct answer is 1.
Quick Math Question 3:
A photograph of a bacteria enlarged 60000 times attains a length of 6 cm. The actual length of bacteria is:
1000 cm
1100
cm
11000
cm
110000
cm
Answer (Detailed Solution Below)
Option 4 :
110000
cm
Quick Math Question 3 Detailed Solution
Given:
The photograph of a bacteria enlarged 60000 times attains a length of 6 cm.
Calculation:
Let the actual length of the bacteria be Q cm.
According to the question,
Q × 60000 = 6
⇒ Q =
110000
∴ The actual length of bacteria
110000
Quick Math Question 4:
A bus starts from a place A and the number of woman in the bus is
13
of the number of men. In the next stop B, 5 men got off the bus and 3 women got in. Now the number of men is twice the number of women. Then total number of passengers in the bus when the bus started from A is
44
33
22
11
Answer (Detailed Solution Below)
Option 1 : 44
Quick Math Question 4 Detailed Solution
Let, the number of man = M
The number of woman = W
At Place A,
W = M/3 (Given) _______________(1)
In the next stop B, 5 men got off the bus and 3 women got in,
Then, no. of man = M - 5
The number of woman = W + 3
M - 5 = 2 (W + 3)
M - 5 = 2W + 6
M - 2W = 11
From equation 1
3W - 2W = 11
W = 11
So, The no. of man = 11 x 3 = 33
Total number of passengers in the bus when the bus started from A = 33 + 11 = 44
Quick Math Question 5:
A whole number is added to 25 and the same number is subtracted from 25. The sum of the resulting numbers is
0
25
50
75
Answer (Detailed Solution Below)
Option 3 : 50
Quick Math Question 5 Detailed Solution
Calculation:
Let assume that the whole number is x
Case:1
x + 25
Case:2
25 - x
Case:3
x + 25 + 25 -x = 50
The sum of the resulting number is 50.
The correct option is 3 i.e. 50
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Top Quick Math MCQ Objective Questions
Top Quick Math MCQ Objective Questions
Find the number of zeroes in 10 × 20 × 30 × ___ × 1000.
100
124
120
150
Answer (Detailed Solution Below)
Option 2 : 124
Quick Math Question 6 Detailed Solution
Given:
10 × 20 × 30 × ___ × 1000
Concept used:
Take 10 as common from each term.
Number of trailing zeroes in n! = Divide n by 5, continue this process until we get the value which is less than 5. Now, all quotients will be added and the resultant number will be the number of zeroes.
Calculations:
10 × 20 × 30 × ___ × 1000
⇒ (10 × 1) × (10 × 2) × (10 × 3) × (10 × 4) _________× (10 × 100)
⇒ 10100 × (1 × 2 × 3 × ___ × 100)
⇒ 10100 × (100!)
Number of zeroes = 100 + {(100)/5 + (20)/5}
⇒ 100 + 20 + 4
⇒ 124
∴ The number of trailing zeroes in 10 × 20 × 30 × ___ × 1000 is 124.
In a class of 100 students, 50 students passed in Mathematics and 70 passed in English, 5 students failed in both Mathematics and English. How many students passed in both the subjects?
50
40
35
25
Answer (Detailed Solution Below)
Option 4 : 25
Quick Math Question 7 Detailed Solution
Given:
Total number of students = 100
Students passed in Mathematics = 50
Students passed in English = 70
Students failed in both subjects = 5
Concept used:
The number of students who passed in both subjects is found by finding the difference between the number of students required for no overlap and the given total.
Calculation:
Students who passed in both the subjects = 70 + 50 – (100 – 5)
⇒ 120 – 95 = 25
∴ The students who passed in both subjects is 25.
Alternate Method
Total number of students = 100
Number of students failed in both subject = 5
⇒ Number of students passed in any one or both subject = (100 - 5) = 95
Students passed in Mathematics = 50
⇒ Students failed in Mathematics but passed in English = (95 - 50) = 45
Students passed in English = 70
⇒ Students failed in English but passed in Mathematics = (95 - 70) = 25
Number of students passed in both subjects = (95 - 45 - 25) = 25
∴ The number of students who passed in both subjects is 25.
Find the square root of the perfect square made by multiplying 4050 with a least positive integer.
80
90
85
95
Answer (Detailed Solution Below)
Option 2 : 90
Quick Math Question 8 Detailed Solution
Concept:
To find the square root of any number, factorize it.
Calculation:
4050 = 2 × 3 × 3 × 3 × 3 × 5 × 5
If we multiply by 2 in 4050
⇒ 4050 × 2 = 8100
Now, √8100 = √(2 × 2 × 3 × 3 × 3 × 3 × 5 × 5)
⇒ √8100 = 2 × 3 × 3 × 5 = 90
∴ Multiply 4050 by 2 to get 8100 of which square root is 90.
In an examination, 41% of students failed in Economics, 35% of students failed in Geography and 39% of students failed in History, 5% of students failed in all the three subjects, 14% of students failed in Economics and Geography, 21% of students failed in Geography and History and 18% of students failed in History and Economics. Find the percentage of students who failed in only Economics.
16%
14%
12%
10%
Answer (Detailed Solution Below)
Option 2 : 14%
Quick Math Question 9 Detailed Solution
According to the question, let the following Venn diagram,
Now,
e = 5%
b + e = 14%
⇒ b = 9%
and,
d + e = 18%
⇒ d = 13%
Therefore,
Percentage of students who failed only in Economics = a = 41% - (b + e + d)
a = 41% - (9 + 5 + 13)%
a = 41% - 27%
a = 14%
Hence, 14% is the correct answer.
If Christmas was on Sunday in 2011, what day will it be in 2012?
Monday
Tuesday
Wednesday
Thursday
Answer (Detailed Solution Below)
Option 2 : Tuesday
Quick Math Question 10 Detailed Solution
Christmas falls on December 25th of every year.
Since 2012 is a leap year, there are 366 days between December 25th of 2011 and December 25th of 2012.
When 366 is divided by 7, the remainder is, ie., 2 more day after Sunday.
So if December 25th of 2011 was on Sunday, December 25th of 2012 will be on Tuesday.
Some students (only boys and girls) from different schools appeared for an Olympiad exam. 20% of the boys and 15% of the girls failed the exam. The number of boys who passed the exam was 70 more than that of the girls who passed the exam. A total of 90 students failed. Find the number of students that appeared for the exam.
350
420
400
500
Answer (Detailed Solution Below)
Option 4 : 500
Quick Math Question 11 Detailed Solution
Given:
20% of the boys and 15% of the girls failed the exam.
Total number of students who failed = 90
Calculation:
The percentage of boys who passed = (100 - 20)% = 80%
The percentage of girls who passed = (100 - 15)% = 85%
Let, the number of appeared boys = x
The number of appeared girls = y
So, 80x/100 - 85y/100 = 70
⇒ 5 (16x - 17y) = 7000
⇒ 16x - 17y = 1400 .....(1)
Also, 20x/100 + 15y/100 = 90
⇒ 5 (4x + 3y) = 9000
⇒ 4x + 3y = 1800 .....(2)
Multiplying 4 to equation (2),
16x + 12y = 7200 .....(3)
Subtracting equation (2) from equation (3),
16x + 12y - 16x + 17y = 7200 - 1400
⇒ 29y = 5800
⇒ y = 5800/29 = 200
∴ The number of girls appeared = 200
Putting y = 200 in equation (2),
4x + 3 × 200 = 1800
⇒ 4x = 1800 - 600 = 1200
⇒ x = 1200/4 = 300
∴ The number of boys who appeared = 300
The total number of students who appeared = 300 + 200 = 500
∴ The number of students that appeared for the exam is 500
Alternate Method
Calculation:-
Let the Number of boys and Girls who appeared in exam be x and y respectively,
So, according to question-
Number of boys passed in exam = [(100 - 20) × x]/100 = 0.80x
Number of girls passed in exam = [(100 - 15) × y]/100 = 0.85y
Condition (1) -
⇒ 0.80x = 0.85y + 70
⇒ 0.80x - 0.85y = 70 ...(i)
Condition (2) -
Total failed students = 90
⇒ 0.20x + 0.15y = 90 ...(ii)
From eqn (1) - [4 × eqn (ii)]
⇒ (-0.85y) - 0.60y = 70 - 360
⇒ 1.45y = 290
⇒ y = 200
Put this value in eqn (i)
⇒ 0.80x = 0.85 × 200 + 70
⇒ 0.80x = 170 + 70 = 240
⇒ x = 300
So, total number of students appeared in exam = 300 + 200 = 500.
The sum of three consecutive multiples of 5 is 285. Find the largest number.
75
100
120
90
Answer (Detailed Solution Below)
Option 2 : 100
Quick Math Question 12 Detailed Solution
Given:
Sum of three consecutive multiples of 5 is 285
Calculation:
Three consecutive numbers are x, x + 1 and x + 2
So, Three consecutive multiples of 5 are 5x, 5(x + 1) and 5(x + 2)
The sum of three consecutive multiple of 5 is 285
∴ 5x + 5x + 5 + 5x + 10 = 285
⇒ 15x = 270
⇒ x = 18
Now, largest number = 5(x + 2) = 5 × 20 = 100
∴ The largest number is 100
Rohit multiplies a number by 2 instead of dividing the number by 2. Resultant number is what percentage of the correct value?
200%
300%
50%
400%
Answer (Detailed Solution Below)
Option 4 : 400%
Quick Math Question 13 Detailed Solution
Given:
Let the number be x.
Correct value = x/2
Resultant number = 2 × x
Calculations:
According to Question,
Required percentage = Resultant number/Correct value × 100
⇒ Required percentage = [(2x)/(x/2)] × 100
⇒ Required percentage = 400%
A monkey climbs a 12 meters high slippery pillar. In his first minute, he climbs 2 meters and in the next minute, he slips one meter down. In this way, how much time will he take to reach the top of the pillar?
10 minutes
21 minutes
12 minutes
11 minutes
Answer (Detailed Solution Below)
Option 2 : 21 minutes
Quick Math Question 14 Detailed Solution
Given
On first minute monkey climb = 2 m
On the second minute it slips = 1 m
Calculation
On first minute monkey climb = 2 m
On the second minute it slips = 1 m
For every two minute, it climbs 1 m
So, average speed = 1 m/2 min
For 10 m, time is taken = 20 min
For the last 2 m jump add 1 min
So time taken = 20 + 1 = 21 min
∴ Monkey takes 21 minutes to reach the top of the pole.
If a = 4011 and b = 3989 then value of ab.
15999879
15899879
15989979
15998879
Answer (Detailed Solution Below)
Option 1 : 15999879
Quick Math Question 15 Detailed Solution
Formula used :
(a + b) × (a - b) = a2 - b2
Calculations :
Let
a = 4000 + 11
b = 4000 - 11
⇒ a × b = (4000 + 11) × (4000 - 11)
⇒ 16000000 - 121
⇒ 15999879
∴ Option1 is the correct choice.
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