The weight of any object on an incline is decomposed into its parallel and perpendicular components. The parallel one, unless equilibrated by another force F, causes the down-the-hill acceleration. The perpendicular one is equilibrated by the normal force; hence, there is no motion in the perpendicular direction.
The objective of this lab is to investigate the parallel component of the weight of an object placed on an inclined plane as a function of the angle of the inclination.
Research Question: How is the force directed parallel to the inclined plane related to the weight of an object?
On the table, you will find an inclined plane, a cart, weights, and a force sensor. Set the inclined plane as shown in the diagram on your lab worksheet.
Make sure to secure the stand with a C-clamp.
Set the force sensor to the range of 50 N.
Be careful with the weights so they do not drop on your foot.
Find a method of measuring the angle of inclination.
In the figure below, a method of measuring both sine and cosine of the angle is shown. Depending on your design, you may want to use either the angle θ or its function, e.g. sin θ (see calculations below)
sin θ = opposite/hypotenuse
sin θ = 6 cm / 50.4 cm = 0.119
arc sin 0.12 = 6.837 ~ 7°
cos θ = adjacent/hypotenuse
cos θ = 50.0 cm / 50.4 cm = 0.992
arc cos 0.99 = 7.22 ~ 7°
tan θ = opposite/adjacent
tan θ = 6 cm / 50 cm = 0.120
arc tan 0.120 = 6.843 ~ 7°
Here are some examples of measuring the angle with a ruler in the lab. Remember to measure the hypotenuse from that end of the incline that touches the table.
Measure the parallel component of the weight for several different angles.
Collect the data in the table in your lab worksheet.
Plot the data points.
Create a graph of the investigated force as a function of the angle of inclination.
Do the plotted points form any shape known from your precalc class? According to the theory, what mathematical function can be used to model the plotted points? Why?