Upon successful completion of this module, the student will be able to:
Identify the characteristics of a parallel DC circuit, especially regarding voltage consistency and current division.
Calculate total resistance, total current, and individual branch currents in a parallel DC circuit.
Apply troubleshooting techniques to identify open and shorted branches in parallel configurations, particularly in an automotive context.
Explain the function and importance of fuses in protecting parallel circuits.
You’ve conquered series circuits. You know that if one bulb in an old string of holiday lights burns out, the whole string goes dark. It’s a single, unforgiving path.
But that’s not how your car works.
When your passenger-side headlight burns out, your driver-side headlight stays lit. Your radio still plays. Your wipers still wipe. Why? Because cars, homes, and virtually all modern electronics are built on a different, more robust design philosophy: parallel circuits.
Mastering parallel circuits is what separates a part-swapper from a true diagnostic technician. Let's power up and dive in.
Forget the one-lane country road of series circuits. A parallel circuit is a bustling city highway system. The battery is the single starting point, but there are multiple off-ramps, each leading to a different destination (a headlight, the radio, the A/C). This analogy gives us three new, unshakable rules.
Voltage is the SAME Everywhere. Every component connected in parallel gets the full source voltage. Each "off-ramp" on our highway connects back to the same two points: the 12V positive terminal and the negative ground frame of the car.
V_Source = V_R1 = V_R2 = V_R3
Total Current ADDS UP. The total current flowing from the battery is the sum of the currents drawn by every single component that's turned on. The battery has to be a "power plant" for all the separate off-ramps.
I_Total = I_R1 + I_R2 + I_R3
Total Resistance is Tricky. Adding more components in parallel decreases the total resistance. Every new off-ramp you add makes it easier for traffic to flow out of the city. The formula is a bit weird at first glance, but it makes sense:
1/R_Total = 1/R1 + 1/R2 + 1/R3
Why is voltage the same? Look at your car's headlights. Both the left and right bulbs are wired so that one side connects to the +12V from the battery (via a fuse and switch) and the other side connects to the car's metal frame (ground). They are both looking at the exact same source.
Why does adding components decrease resistance? Imagine a crowded store with only one checkout lane (high resistance). The flow of people is slow. Now, the manager opens five more checkout lanes (adding paths in parallel). The overall opposition to people leaving the store has just dropped dramatically, even though the total number of people has increased. More paths = less total resistance.
Let's put some numbers to this. You're driving at night with your headlights on while listening to the radio.
Your car's electrical system is 12V.
Each headlight has a resistance of 4Ω.
Your radio has a resistance of 30Ω.
Your Mission: What is the total current draw on your battery/alternator?
Confirm the Voltage: Every component gets the full 12V.
Calculate Branch Currents: Use Ohm's Law for each separate "branch."
Headlight 1: I_H1 = V / R_H1 = 12V / 4Ω = 3A
Headlight 2: I_H2 = V / R_H2 = 12V / 4Ω = 3A
Radio: I_Radio = V / R_Radio = 12V / 30Ω = 0.4A
Calculate Total Current: Add up the branch currents.
I_Total = 3A + 3A + 0.4A = 6.4A
The battery must supply 6.4 Amps to keep everything running. You've just used the rules of parallel circuits to figure out the total load on your car's electrical system.
Your car's fuse box is a masterclass in parallel circuit management. It's the central hub where all the parallel branches come together, and each one is protected by a fuse.
Scenario 1: A Headlight Burns Out (An Open)
The filament in your passenger-side headlight breaks. This is an open circuit.
Analysis: The "off-ramp" to that headlight is now closed. Current can no longer flow to that one component.
Result: The passenger headlight goes out. The driver-side headlight and the radio are on separate parallel paths, so they are completely unaffected. The total current draw on the battery simply decreases by the 3A that the dead bulb is no longer using.
Scenario 2: A Wire Shorts Out (A Short)
A wire behind your radio has its insulation rub off and it touches the metal frame of the car. This is a short circuit.
Analysis: You have just created a new "off-ramp" with virtually zero resistance (R ≈ 0Ω).
Result: Ohm's Law tells us what happens next: I = V/R = 12V / 0Ω. The current tries to spike to an infinite level! This massive surge of current would melt wires and start a fire, but thankfully, the fuse for the radio circuit is designed to handle this. The high current melts the tiny wire inside the fuse, instantly creating an open and stopping the dangerous flow.
You're the technician. A customer comes in and says, "My 15A fuse for the power windows keeps blowing, but only when I try to use the driver-side window."
A rookie grabs a handful of 15A fuses and keeps popping them. A pro grabs a multimeter.
Your Troubleshooting Plan:
Safety First: Disconnect the battery or pull the main power relay.
Hypothesis: The fault is either in the window motor itself (maybe the motor has seized, drawing excessive current) or in the wiring leading to the motor (a short circuit to ground).
The Test (Isolating the Problem):
Remove the blown 15A fuse.
Unplug the wiring harness from the driver-side window motor. This physically separates the motor from the wiring.
Set your multimeter to measure resistance (Ohms).
Test 1 (Check the Wiring): Place one meter lead on the power wire in the harness and the other lead on a clean metal ground point on the car's frame. A good circuit should show infinite resistance (an open loop). If you read a very low resistance (like 0.5Ω), you have found the problem: the wire is shorted to ground somewhere in the door.
Test 2 (Check the Motor): If the wiring checks out, measure the resistance across the two terminals of the window motor itself. A good motor will have a specific, low resistance. A motor with an internal short might read near 0Ω. A burned-out motor might read as an open circuit.
Create Your Solution: Based on your evaluation, you can now confidently tell the customer, "The motor itself is fine; the problem is a shorted wire inside your door panel," or "The wiring is good, but your window motor has failed and needs to be replaced."
You didn't just guess. You used your knowledge of parallel circuits and a logical process to diagnose the fault, saving time, money, and parts. That’s the pro-level difference.
(Remembering)
What is the relationship between the source voltage and the voltage across each branch in a parallel circuit?
If you add another component (like fog lights) in parallel to an existing automotive circuit, what happens to the total resistance of the circuit?
(Understanding)
3. Explain why a short circuit in one parallel branch (like the radio) will blow a fuse rather than just causing the radio to stop working.
4. Using the highway analogy, explain why the total current from the battery is the sum of all the individual branch currents.
(Applying)
5. A car's 12V battery powers a horn (6Ω resistance) and a cabin dome light (36Ω resistance) in parallel. What is the total current drawn from the battery when both are active?
6. Three resistors (20Ω, 30Ω, and 60Ω) are connected in parallel. What is their total equivalent resistance?
(Analyzing)
7. A technician measures the total current from a 12V battery powering two parallel headlights and finds it to be 5A. The manual says the total current should be 6A when both headlights are working. What is the most likely electrical fault in this circuit? Explain your reasoning.
8. A vehicle's accessory circuit is protected by a 10A fuse. The circuit powers two outlets. A device rated to draw 5A is plugged into Outlet #1. A device rated to draw 6A is plugged into Outlet #2. Analyze this situation and predict what will happen when both devices are turned on.
(Evaluating)
9. A technician is trying to find a short circuit in a parallel branch that keeps blowing a 20A fuse. They decide to bypass the fuse with a thick piece of wire to "see what smokes" to find the short. Evaluate this troubleshooting technique. Is it a valid or a dangerous approach? Justify your answer.
(Creating)
10. The right-side turn signals (front and back bulbs, wired in parallel) on a car are not working, but the left-side signals work perfectly. The fuse for the turn signals is good. Create a logical, step-by-step diagnostic plan to locate the source of the fault.
Various circuits using basic electrical kits, mobile modular, control circuit panels